c - 二维字符数组动态重新分配失败

Question

这是代码片段。字典格式为:{word word\n word word\n...}

程序在第二次重新分配二维数组 roWords 时似乎失败了，我不知道为什么。

声明中:char ** roWords = NULL, **enWords == NULL;

while (fgets(buffer, 100, dictionary))
    {
        counter++;

        roWords = (char**)realloc(roWords, sizeof(char*)* counter );
        enWords = (char**)realloc(enWords, sizeof(char*)* counter );

        p = strtok(buffer, " \n");


        roWords[counter - 1] = NULL;
        roWords[counter - 1] = (char*)realloc(roWords, sizeof(char)* strlen(p));
        strcpy(roWords[counter - 1], p);


        p = strtok(NULL, " \n");


        enWords[counter - 1] = NULL;
        enWords[counter - 1] = (char*)realloc(enWords, sizeof(char)* strlen(p));
        strcpy(enWords[counter - 1], p);


    }

Answer 1

解决方案是:

while (fgets(buffer, 100, dictionary))
{
    counter++;

    if (counter == 1)
    {
        roWords = (char**)malloc(sizeof(char*));
        enWords = (char**)malloc(sizeof(char*));
    }
    else
    {
        roWords = (char**)realloc(roWords, sizeof(char*)* counter);
        enWords = (char**)realloc(enWords, sizeof(char*)* counter);
    }

    p = strtok(buffer, " \n");


    roWords[counter - 1] = (char*)malloc(sizeof(char) * (strlen(p) + 1));
    strcpy(roWords[counter - 1], p);
    roWords[counter - 1][strlen(p)] = '\0';

    p = strtok(NULL, " \n");


    enWords[counter - 1] = (char*)malloc(sizeof(char)* (strlen(p) + 1));
    strcpy(enWords[counter - 1], p);
    enWords[counter - 1][strlen(p)] = '\0';

}