c - 重新定义；之前的定义是 'data variable'

Question

好吧，我快要疯了。我应该为类(class)编写一个程序，确定您输入的年份中的天数(考虑闰年)，但我觉得我不知道自己在做什么。在我的压力水平进一步上升之前，我将不胜感激能获得的任何帮助。在能够测试我的程序(我怀疑它是否有效)之前我遇到的最终错误是:

error C2365: 'leap' : redefinition; previous definition was 'data variable'

和

error C2365: 'count' : redefinition; previous definition was 'data variable'

源代码:

#include <stdio.h>

int main(void){

    int d, m, y, x, day, leap, count;


    //Input values for date
    printf("\n Input the Day: ");
    scanf_s("%f", &d);

    printf("\n Input the Month: ");
    scanf_s("%f", &m);

    printf("\n Input the Year: ");
    scanf_s("%f", &y);
    //End input

    int count(int m, int day);

    int leap(int y, int x);



    if (x == 1){
            printf("\nThe day of the year is %f", day + 1);
    }
    else{
            printf("\nThe day of the year is %f", day);
    }

    system("pause");
    return(0);
}


//Count the number of days
int count(int m, int day, int d){
    if (m == 1){
        day = d;
    }
    if (m == 2){
        day = 31 + d;
    }
    if (m == 3){
        day = 59 + d;
    }
    if (m == 4){
        day = 90 + d;
    }
    if (m == 5){
        day = 120 + d;
    }
    if (m == 6){
        day = 151 + d;
    }
    if (m == 7){
        day = 181 + d;
    }
    if (m == 8){
        day = 212 + d;
    }
    if (m == 9){
        day = 243 + d;
    }
    if (m == 10){
        day = 273 + d;
    }
    if (m == 11){
        day = 304 + d;
    }
    if (m == 12){
        day = 334 + d;
    }
    return(day);
}

//Determine if it's a leap year
int leap(int y, int x){
    if (y % 400 == 0){
        x = 1;
    }
    else if (y % 100 == 0){
        x = 0;
    }
    else if (y % 4 == 0){
        x = 1;
    }
    else{
        x = 0;
    }
    return(x);
}

Answer 1

以下是main()中不允许的函数声明(局部函数定义是非法的)。您应该将它们放在 main() 之前。

int count(int m, int day);
int leap(int y, int x);

此外，根据您的定义，count() 的函数声明应该是:

int count(int m, int day, int d);

并删除int Leap, count;，它是数据类型的声明(这里是int)而不是函数的声明。

如果你想在main()中调用它们，只需使用:

count(m, day, d);
leap(y, x);