c - 在其他输入之后使用 fgets()

Question

我对 C 编程有点陌生，在做练习时遇到了麻烦。这是我的代码:

    printf("Enter the First Name: ");
    scanf("%s", rd[input-1].firstName);

    printf("Enter the Last Name: ");
    scanf("%s", rd[input-1].lastName);

    printf("Enter the Phone Number: ");
    scanf("%d", &rd[input-1].phoneNum);

    printf("Enter the Address: ");

    fgets(rd[input-1].address, 100, stdin);

    dataWrite();
    printRecord(input-1);

其中rd[n]是一个结构体数组，为地址字段分配的char[]空间为100。我知道 fgets() 消耗“Enter”(\n) 字符。这就是为什么当我输入phoneNum时，fgets()受到影响，并且我无法获取地址字段的输入。还有其他方法可以获得长地址吗？

问题已解决:我输入了

     fgets(rd[input-1].address, 100, stdin);

两次。现在它工作得很好。

Answer 1

#include <stdio.h>

struct data
{
  char firstName[100];
  char lastName[100];
  char phoneNum[10];
  char address[100];
};

struct data rd[10];

void printRecord(int i)
{
  printf("\n");//ugh
  printf("fn: %s\n",rd[i].firstName);
  printf("ln: %s\n",rd[i].lastName);
  printf("pn: %s\n",rd[i].phoneNum);
  printf("addr: %s\n",rd[i].address);
}

int main(int argc, char** argv)
{
  int input=1;
  char buff[100];

  printf("Enter the First Name: ");
  //char * fgets ( char * str, int num, FILE * stream );
  fgets(buff, 100, stdin);
  sscanf(buff, "%s", rd[input-1].firstName);
  //Why "input-1"? keep it as just "input" and make sure it equals the correct value before entering this area

  printf("Enter the Last Name: ");
  fgets(buff, 100, stdin);
  sscanf(buff,"%s", rd[input-1].lastName);

  printf("Enter the Phone Number: ");
  fgets(buff, 100, stdin);
  //phoneNum is a string, not an integer, get it with a %s
  sscanf(buff,"%s", &rd[input-1].phoneNum); 

  printf("Enter the Address: ");
  fgets(rd[input-1].address, 100, stdin);

  printRecord(input-1);

}