javascript - spy 的回调不是用 sinon 和 qunit 调用

Question

对于单元测试，我正在尝试使用 sinon.js 制作假服务器和 qUnit , 但在调用 ajax 之后方法callback的 spy没有调用。

所以第三个和第四个断言不满足，

ok(callback.called, "spy called once"); //failed
ok(callback.calledWith([{ id: 12, comment: "Hey there" }]);  //failed

谁能告诉我我做错了什么，这是我试过的。

test("should fetch comments from server", function () {
        var server = this.sandbox.useFakeServer();
        server.respondWith("GET", "/something",
                           [200, { "Content-Type": "application/json" },
                            '[{ id: 12, comment: "Hey there" }]']);


        var callback = this.spy();
        //----^---this is not invoking

        //after invoke below $.ajax() code above callback should be invoked 
        //and 3rd and 4th assertion should be satisfied but not happening.

        $.ajax({
            url: "/something",
            success: callback
         });

        server.respond();
        equal(server.requests.length, 1, "server request length");
        ok(callback.called, "spy called once"); //failed
        ok(callback.calledWith([{ id: 12, comment: "Hey there" }])); //failed
    });

JSFIDDLE

Answer 1

看起来像解析错误导致 ajax 错误处理程序运行而不是成功处理程序。如果您像这样修复 JSON...

    server.respondWith("GET", "/something",
                       [200, { "Content-Type": "application/json" },
                        '[{ "id": 12, "comment": "Hey there" }]']);

...测试通过。 JSFiddle .