c# - 在 C# 控制台应用程序中获取 google 驱动程序中文件的 downloadUrl

Question

我正在努力连接到谷歌驱动器，列出所有格式的每个文件，然后将其物理下载到我的硬盘上。我使用了 google API 为我准备的方法。但我认为我的工作方式只能访问每个文件的内容，所以我不能那样做。

你能帮我知道我需要哪个配置吗？

public static Google.Apis.Drive.v2.Data.FileList ListFiles(DriveService service, FilesListOptionalParms optional = null)
        {
            try
            {

                if (service == null)
                    throw new ArgumentNullException("service");


                var request = service.Files.List();

                request = (FilesResource.ListRequest)SampleHelpers.ApplyOptionalParms(request, optional);

                return request.Execute();
            }
            catch (Exception ex)
            {
                throw new Exception("Request Files.List failed.", ex);
            }
        }

我调用此方法，并针对我要将其下载到我的 PC 上的每个文件:

 FileList files_list = DriveListExample.ListFiles(service, null);
            if (files_list.Items.Count != 0)
            {
                foreach (var file in files_list.Items)
                {                        
                    DriveListExample.DownloadFile(service, file, DownloadDirectoryName);




                    Console.WriteLine("\"{0}\" ", file.Title + " downloaded completely!");


                }
            }

在这里，如果我可以访问每个文件的 downloadUrl，我可以测试另一种下载方式。但它是空的，这是我的下载方法:

public static void DownloadFile(DriveService 服务, File 文件, string saveTo) {

    var request = service.Files.Get(file.Id);
    var stream = new System.IO.MemoryStream();
    Console.WriteLine(file.FileExtension);


    request.MediaDownloader.ProgressChanged += (IDownloadProgress progress) =>
    {
        switch (progress.Status)
        {
            case DownloadStatus.Downloading:
                {
                    Console.WriteLine(progress.BytesDownloaded);
                    break;
                }
            case DownloadStatus.Completed:
                {
                    Console.WriteLine("Download complete.");
                    SaveStream(stream, saveTo);
                    break;
                }
            case DownloadStatus.Failed:
                {
                    Console.WriteLine("Download failed.");
                    break;
                }
        }
    };

    try
    {
        request.Download(stream);
    }
    catch (Exception ex)

    {
        Console.Write("Error: " + ex.Message);
    }

}

本次下载状态为失败。我还检查了范围，我发现这些行只允许我下载我在这个应用程序中创建的文件:

private static readonly string[] Scopes = new[] { DriveService.Scope.DriveFile, DriveService.Scope.Drive };

但我需要在列出所有文件后，才能下载每个文件。

能否请您帮我解决问题或其他工作代码？

Answer 1

您需要使用有效的文件名并处理 google doc 文件:

 public static void DownloadFile(DriveService service, Google.Apis.Drive.v2.Data.File file, string saveTo)
        {

            var request = service.Files.Get(file.Id);
            var stream = new System.IO.MemoryStream();

            // Add a handler which will be notified on progress changes.
            // It will notify on each chunk download and when the
            // download is completed or failed.
            request.MediaDownloader.ProgressChanged += (IDownloadProgress progress) =>
            {
                switch (progress.Status)
                {
                    case DownloadStatus.Downloading:
                        {
                            Console.WriteLine(progress.BytesDownloaded);
                            break;
                        }
                    case DownloadStatus.Completed:
                        {
                            Console.WriteLine("Download complete.");
                            SaveStream(stream, saveTo + @"/" + file.Title);
                            break;
                        }
                    case DownloadStatus.Failed:
                        {
                            if (file.ExportLinks.Any())
                                SaveStream(new HttpClient().GetStreamAsync(file.ExportLinks.FirstOrDefault().Value).Result, saveTo + @"/" + file.Title);
                            Console.WriteLine("Download failed.");
                            break;
                        }
                }
            };

            try
            {
                request.Download(stream);
            }
            catch (Exception ex)

            {
                Console.Write("Error: " + ex.Message);
            }

        }