c - 我想消除我在程序中绘制的表格的重复外观。有没有办法可以将其放入单独的函数中？

Question

我正在创建一个程序，要求用户提供坐标，然后在 table 上用大写 O 标记该坐标。我已经让程序在单元格 A1-A3 上标记字母 O(如果用户输入过这些字母)。但是我编写的程序会很长，因为我在每个条件下重复输入表格。有没有办法可以将表分开并将其放入函数中？

#include <stdio.h>
#include <string.h>

int main(){
    char first [3], second [3], third [3];
    char A1 = ' ', A2 = ' ', A3 = ' ';
    char B1 = ' ', B2 = ' ', B3 = ' ';
    char C1 = ' ', C2 = ' ', C3 = ' ';

    static const char a1[] = "a1";
    static const char a2[] = "a2";
    static const char a3[] = "a3";
    static const char b1[] = "b1";
    static const char b2[] = "b2";
    static const char b3[] = "b3";
    static const char c1[] = "c1";
    static const char c2[] = "c2";
    static const char c3[] = "c3";

    printf("   1   2   3");
    printf("\n +---+---+---+");
    printf("\nA| %c | %c | %c |", A1, A2, A3);
    printf("\n +---+---+---+");
    printf("\nB| %c | %c | %c |", B1, B2, B3);
    printf("\n +---+---+---+");
    printf("\nC| %c | %c | %c |", C1, C2, C3);
    printf("\n +---+---+---+");

    printf("\n\nCoordinates should be entered in this format, lower cap for columns followed by row number.\nExample: a1, b2, c3, etc.");
    printf("\n\nPlease enter 1st coordinate: ");
    scanf("%3s", &first);

    if (!strcmp(first,a1)){
    A1 = 'O';
    system("cls");
    printf("   1   2   3");
    printf("\n +---+---+---+");
    printf("\nA| %c | %c | %c |", A1, A2, A3);
    printf("\n +---+---+---+");
    printf("\nB| %c | %c | %c |", B1, B2, B3);
    printf("\n +---+---+---+");
    printf("\nC| %c | %c | %c |", C1, C2, C3);
    printf("\n +---+---+---+");
    }

    if (!strcmp(first,a2)){
    A2 = 'O';
    system("cls");
    printf("   1   2   3");
    printf("\n +---+---+---+");
    printf("\nA| %c | %c | %c |", A1, A2, A3);
    printf("\n +---+---+---+");
    printf("\nB| %c | %c | %c |", B1, B2, B3);
    printf("\n +---+---+---+");
    printf("\nC| %c | %c | %c |", C1, C2, C3);
    printf("\n +---+---+---+");
    }

    if (!strcmp(first,a3)){
    A3 = 'O';
    system("cls");
    printf("   1   2   3");
    printf("\n +---+---+---+");
    printf("\nA| %c | %c | %c |", A1, A2, A3);
    printf("\n +---+---+---+");
    printf("\nB| %c | %c | %c |", B1, B2, B3);
    printf("\n +---+---+---+");
    printf("\nC| %c | %c | %c |", C1, C2, C3);
    printf("\n +---+---+---+");
    }

    getch();
    return 0;
}

Answer 1

添加函数printTable。

void printTable(char A1, char A2, char A3,
                char B1, char B2, char B3,
                char C1, char C2, char C3)
{
    system("cls");
    printf("   1   2   3");
    printf("\n +---+---+---+");
    printf("\nA| %c | %c | %c |", A1, A2, A3);
    printf("\n +---+---+---+");
    printf("\nB| %c | %c | %c |", B1, B2, B3);
    printf("\n +---+---+---+");
    printf("\nC| %c | %c | %c |", C1, C2, C3);
    printf("\n +---+---+---+");
}

在适当的位置从 main 调用该函数。

int main(){
    char first [3], second [3], third [3];
    char A1 = ' ', A2 = ' ', A3 = ' ';
    char B1 = ' ', B2 = ' ', B3 = ' ';
    char C1 = ' ', C2 = ' ', C3 = ' ';

    static const char a1[] = "a1";
    static const char a2[] = "a2";
    static const char a3[] = "a3";
    static const char b1[] = "b1";
    static const char b2[] = "b2";
    static const char b3[] = "b3";
    static const char c1[] = "c1";
    static const char c2[] = "c2";
    static const char c3[] = "c3";

    printTable(A1, A2, A3, B1, B2, B3, C1, C2, C3);

    printf("\n\nCoordinates should be entered in this format, lower cap for columns followed by row number.\nExample: a1, b2, c3, etc.");
    printf("\n\nPlease enter 1st coordinate: ");
    scanf("%3s", &first);

    if (!strcmp(first,a1)){
    A1 = 'O';
    printTable(A1, A2, A3, B1, B2, B3, C1, C2, C3);
    }

    if (!strcmp(first,a2)){
    A2 = 'O';
    printTable(A1, A2, A3, B1, B2, B3, C1, C2, C3);
    }

    if (!strcmp(first,a3)){
    A3 = 'O';
    printTable(A1, A2, A3, B1, B2, B3, C1, C2, C3);
    }

    getch();
    return 0;
}

进一步简化

创建一个字符数组来存储数据并使用该数组而不是有这么多变量。

void printTable(char data[][3])
{
   char* A = data[0];
   char* B = data[1];
   char* C = data[2];

    system("cls");
    printf("   1   2   3");
    printf("\n +---+---+---+");
    printf("\nA| %c | %c | %c |", A[0], A[1], A[2]);
    printf("\n +---+---+---+");
    printf("\nB| %c | %c | %c |", B[0], B[1], B[2]);
    printf("\n +---+---+---+");
    printf("\nC| %c | %c | %c |", C[0], C[1], C[2]);
    printf("\n +---+---+---+");
}

int main(){
    char first [3], second [3], third [3];
    char data[][3] = {' ', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' '};

    static const char a1[] = "a1";
    static const char a2[] = "a2";
    static const char a3[] = "a3";
    static const char b1[] = "b1";
    static const char b2[] = "b2";
    static const char b3[] = "b3";
    static const char c1[] = "c1";
    static const char c2[] = "c2";
    static const char c3[] = "c3";

    printTable(data);

    printf("\n\nCoordinates should be entered in this format, lower cap for columns followed by row number.\nExample: a1, b2, c3, etc.");
    printf("\n\nPlease enter 1st coordinate: ");
    scanf("%3s", &first);

    if (!strcmp(first,a1)){
    data[0][0] = 'O';
    printTable(data);
    }

    if (!strcmp(first,a2)){
    data[0][1] = 'O';
    printTable(data);
    }

    if (!strcmp(first,a3)){
    data[0][2] = 'O';
    printTable(data);
    }

    getch();
    return 0;
}