c - 我的游戏板无限循环

Question

我的游戏板出现无休止循环的问题。连续的任何三个字母都会被删除，并继续该过程，直到没有更多的字母为止。当角色用完时，它应该停止运行，但我不确定我哪里出错了。有什么帮助吗？

编辑:问题似乎出在 updateBoard 函数

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <time.h>
#define MAX 100

void command(int argc) {
    if (argc != 3) { // Takes in 3 arguments. File name/Size/Number of letters
        printf("You need 3 arguments");
    } else {
    }
}

int args(char* arg) {
    int size;
    size = atoi(arg); // Convert string to int
    return size; // Return int
}

int checkBoard(char myArray[MAX][MAX], int size) {
    int i, j; // Loop through board
    for (i = 0; i < size; i++) {
        for (j = 0; j < size; j++) {
            if (myArray[i][j] == myArray[i + 1][j] &&
                myArray[i + 1][j] == myArray[i + 2][j]) {
                myArray[i][j] = ' '; // Change 3 cells to blanks
                myArray[i + 1][j] = ' ';
                myArray[i + 2][j] = ' ';
            }
            if (myArray[i][j] == myArray[i][j + 1] &&
                myArray[i][j + 1] == myArray[i][j + 2]) {
                myArray[i][j] = ' '; // Change cells to blanks
                myArray[i][j + 1] = ' ';
                myArray[i][j + 2] = ' ';
            }
        }
    }

    int pass2;
    pass2 = updateBoard(myArray, size); // Pass array board to next function

    updateBoard(myArray, size);
}

int updateBoard(char myArray[MAX][MAX], int size) {
    int i, j;
    for (i = 0; i < size; i++) // Loops through and prints board
    {
        for (j = 0; j < size; j++) {
            if (myArray[i][j] == ' ' && myArray[i + 1][j] == ' ' &&
                myArray[i + 2][j] == ' ') {
                myArray[i][j] =
                    myArray[i][j - 1]; // Drop cell if existing cells are blank
                myArray[i + 1][j] = myArray[i][j - 1];
                myArray[i + 2][j] = myArray[i][j - 1];
            }
            if (myArray[i][j] == ' ' && myArray[i][j + 1] == ' ' &&
                myArray[i][j + 2] == ' ') {
                myArray[i][j] = myArray[i][j - 4]; // Same as above
                myArray[i][j + 1] = myArray[i][j - 4];
                myArray[i][j + 2] = myArray[i][j - 4];
            }
        }
    }
    for (i = 0; i < size; i++) // Loop through and print updated board
    {
        for (j = 0; j < size; j++) {
            printf("%c ", myArray[i][j]);
        }
        printf("\n");
    }
    printf("\n");

    int flag;
    if (myArray[MAX][MAX]) {
        flag = 1;
    } else {
        flag = 0;
    }

    while (flag != 1) {
        int pass3;
        pass3 = checkBoard(myArray, size);
        checkBoard(myArray, size);
    }
}

int main(int argc, char* argv[]) {
    int i, j;
    int size, sarg; // Two arguments

    command(argc); // Call command function

    printf("test1\n");
    size = args(argv[1]); // Passing arguments
    printf("test2\n");
    sarg = args(argv[2]);
    printf("test3\n");
    printf("%s\n", argv[1]);
    printf("%s\n", argv[2]);
    printf("Arg1: %d\nArg2: %d\n\n", size, sarg);

    srand(time(NULL)); // Use of time to generate random characters

    static char myArray[MAX][MAX];
    char letter =
        'A' + (rand() % sarg); // 26 possible letters for second argument

    for (i = 0; i < size; i++) {
        for (j = 0; j < size; j++) {
            myArray[i][j] = 'a' + (rand() % sarg); // Loop through and fill
                                                   // board
        }
    }

    for (i = 0; i < size; i++) {
        for (j = 0; j < size; j++) {
            printf("%c ", myArray[i][j]); // Loop through and print board
        }
        printf("\n");
    }
    printf("\n");

    int pass; // Pass initial board to checkboard function
    pass = checkBoard(myArray, size);

    int count;

    checkBoard(myArray, size); // Call function to generate updated board

    printf("The number of moves made is %d: ", count);
}

PS:每次棋盘掉落单元格时，main 中的计数都会增加，以计算已进行的移动次数。关于如何计算函数执行次数的任何建议？干杯

Answer 1

如果flag的值不为1，则这是一个无限循环。

 while(flag != 1){
        int pass3;
        pass3 = checkBoard(myArray,size);
        checkBoard(myArray,size);
    }