C - 扫雷 AI 不点击图 block

Question

这款游戏是扫雷。我试图实现的人工智能将采用已经在计算机上运行的扫雷游戏实例(本例为 Windows 7)，获取窗口的矩形尺寸，计算窗口的位置，将其推送到前台在屏幕上，单击左上角的方 block ，然后通过奇特的算法来决定哪个方 block 是地雷，哪个方 block 是空的。

最近，只有在实现 MessageBox 后，我才能正确处理窗口和光标。在单击第一个图 block 之前。

有了消息框，程序会将扫雷窗口推到最前面，生成消息框，点击消息框上的回车按钮后，程序会将光标定位到正确的左上角方 block 上然后停止。在消息框后面的代码中，有一个注释掉的部分，当取消注释时，它会迭代整个扫雷窗口并将其标记为地雷(标志!) - 这告诉我它确实注册了 ClickTile对于地雷正确 - 但不明确区域。此后，程序应该单击左上角的第一个图 block 。所发生的只是鼠标闪烁。

正确的行为是将扫雷窗口推到最前面，生成消息框，单击消息框后，应该单击游戏内左上角的方 block 。

问题是，为什么不注册 LEFTMOUSEDOWN并且只有RIGHTMOUSEDOWN在 ClickTile ？

UiInfo.h

#ifndef UiInfo_
#define UiInfo_
#include <Windows.h>

struct UiInfo {
    float scale;
    POINT start;
    int tile_size;
};

extern struct UiInfo * ui_info;

void UiInfo_initialize(struct UiInfo * ui_info, 
                    float scale,
                    POINT start,
                    int tile_size);
#endif

UiInfo.c

#include "UiInfo.h"

void UiInfo_initialize(struct UiInfo * ui_info, 
                    float scale,
                    POINT start,
                    int tile_size) {

    ui_info->scale = scale;
    ui_info->start = start;
    ui_info->tile_size = tile_size;
}

main.c

void ClickTile(int is_mine, int x, int y) {
    INPUT input = {0};

    int xpos = (int)(ui_info->start.x + ui_info->tile_size * x);
    int ypos = (int)(ui_info->start.y + ui_info->tile_size * y);

    SetCursorPos(xpos, ypos);

    input.type = INPUT_MOUSE;
    if(is_mine) {
        input.mi.dwFlags = MOUSEEVENTF_RIGHTDOWN;
    }
    else {
        input.mi.dwFlags = MOUSEEVENTF_LEFTDOWN;
    }

    SendInput(1, &input, sizeof(INPUT));

    ZeroMemory(&input, sizeof(INPUT));

    input.type = INPUT_MOUSE;
    if(is_mine) {
        input.mi.dwFlags = MOUSEEVENTF_RIGHTUP;
    }
    else {
        input.mi.dwFlags = MOUSEEVENTF_LEFTUP;
    }

    SendInput(1, &input, sizeof(INPUT));
}

int WINAPI WinMain(HINSTANCE hInstance,
                     HINSTANCE hPrevInstance,
                     LPSTR     lpCmdLine,
                     int       nCmdShow) {

    float scale;
    POINT start;
    RECT rect;
    int size;
    int x,y;
    HWND hwnd_minesweeper = FindWindow(NULL, "Minesweeper");

    GetWindowRect(hwnd_minesweeper, &rect);

    scale = ((float)(rect.right - rect.left)) / ((float)(74 + 18 * 30));

    // the point start is located at the center of the tile in the top left
    // corner of the minesweeper map

    start.x = ((long)scale) * (38 + 9) + rect.left;
    start.y = rect.bottom - ((long)scale) * (38 + 15*18 + 9);

    size = (int)scale * 18;

    ui_info = (struct UiInfo *)malloc(sizeof(struct UiInfo));
    UiInfo_initialize(ui_info, scale, start, size);

    SetForegroundWindow(hwnd_minesweeper);


    MessageBox(NULL, "A", "B", MB_OK);

    /*for(y = 0; y < 16; y++) {
        for(x = 0; x < 30; x++) {
            Sleep(10);
            ClickTile(1,x,y);
        }
    }*/

    //Click the mine in the top left corner to start the game
    ClickTile(0, 0, 0);

    return 0;
}

Answer 1

我会进行三种猜测。

猜数字 1

您需要使用计时器来让您的鼠标移动和鼠标点击有时间生效。这涉及在应用程序启动时启动计时器，然后实现一个状态机，在计时器触发时生成新的鼠标事件，例如

// start the timer in some initialization function
SetTimer( 75, 5, NULL );   

// handler function to update the overall state
void CMainFrame::OnTimer(UINT nIDEvent)
{
    switch ( m_State )
    {
        case STATE_IDLE:    // do nothing until the user tells us to start
        case STATE_DONE:    // do nothing after the game is finished
            break;

        case STATE_START:   // the first click to get things started
            mouse_event( MOUSEEVENTF_MOVE | MOUSEEVENTF_ABSOLUTE, m_Square[1][1].mousex, m_Square[1][1].mousey, 0, 0 );
            mouse_event( MOUSEEVENTF_LEFTDOWN, 0, 0, 0, 0 );
            mouse_event( MOUSEEVENTF_LEFTUP  , 0, 0, 0, 0 );
            m_State = STATE_MOVING;
            break;

        case STATE_MOVING:  // all the fun happens here
            if ( !MakeAMove() )
            {
                m_State = STATE_DONE;
                Invalidate();
            }
            break;
    }

    CFrameWnd::OnTimer(nIDEvent);
}

猜数字2

无论屏幕分辨率如何，鼠标坐标系均为 65536 x 65536。因此，您需要缩放鼠标坐标以转换为像素位置。这是计算比例因子的一种方法

HDC hdc = ::GetDC( NULL );
CDC *dc = CDC::FromHandle( hdc );
CWnd *wnd = dc->GetWindow();
wnd->GetClientRect( &rect );
xscale = 65535.0 / (double)rect.right;
yscale = 65535.0 / (double)rect.bottom;

猜数字3

在生成鼠标点击事件之前，您需要将鼠标移动到正确的屏幕坐标，例如

// the following code goes in some initialization function that knows the location of the minesweeper window
// note that screenx and screeny are the pixel coordinates of the center point of each square and these
// are converted to mouse coordinates for each square
for ( y = 1; y <= m_MaxY; y++ )
    for ( x = 1; x <= m_MaxX; x++ )
    {
        m_Square[y][x].mousex  = (int)(m_Square[y][x].screenx * xscale + 0.5);
        m_Square[y][x].mousey  = (int)(m_Square[y][x].screeny * yscale + 0.5);
    }

// this code generates a left click in a given square
mouse_event( MOUSEEVENTF_MOVE | MOUSEEVENTF_ABSOLUTE, m_Square[y][x].mousex, m_Square[y][x].mousey, 0, 0 );
mouse_event( MOUSEEVENTF_LEFTDOWN, 0, 0, 0, 0 );
mouse_event( MOUSEEVENTF_LEFTUP  , 0, 0, 0, 0 );