c - 结构体和字符串

Question

这个问题已经有答案了:

Why does reading into a string buffer with scanf work both with and without the ampersand (&)? (2 个回答)

已关闭 8 年前。

#include <stdio.h>
#define MAX 3 // students in class 
#define LEN 20 // max lengths stydent's name

typedef struct {
    char name[LEN];
    int am;
    float tv;
}student;

void read (student board[]) {       //this function should fill the board of structs
    int i;
    for (i=0; i<MAX; i++) {
        printf("\n give student's name");
        scanf ("%s",&board[i].name);
    }

}

void read (student board[]);

int main (void) {
    student class[MAX];
    read (class);
return 0;   
} 

当我尝试编译它时，出现此错误

let2.c:15:3: warning: format ‘%s’ expects argument of type ‘char ’, but argument 2 has type ‘char ()[20]’ [-Wformat=]
let2.c:15:3: warning: format ‘%s’ expects argument of type ‘char ’, but argument 2 has type ‘char ()[20]’ [-Wformat=]

Answer 1

丢失 scanf 调用中的 &。您需要一个指向字符串第一个字符的指针，而不是指向数组本身的指针:

scanf("%s", board[i].name);

或者，等价:

scanf("%s", &board[i].name[0]);