c - 第 90 行 :subscripted value is neither array nor pointer nor vector

Question

我创建了下面的程序来从文件中读取逗号分隔的数据，然后插入到结构中。有一个名为 struct person insert_into_struct(char line[]) 的函数。当我在该函数中编译此函数时，在最后一个 for 循环中 p.Id[j]=line[i]; 出现错误

line 90 error: subscripted value is neither array nor pointer nor vector

这是代码

#include<stdio.h>
#include<string.h>  

struct person{
    char name[100];
    char address[100];
    int  Id;
};

struct person insert_into_struct(char line[]);

int main(int argc,char *argv[]){

    FILE *fp1;
    fp1=fopen(argv[1],"r");

    char ch;
    char line[100];
    int i=0;

    struct person person_arry[100];
    int linenum=0;
    if(fp1==0)
    {
        printf("Error\n");
    }
    else
    {
        while((ch=fgetc(fp1))!=EOF){

        switch(ch){
            case '\n':
                line[i]='\0';

                person_arry[linenum]=insert_into_struct(line);
                printf("line:%d, name: %s, address: %s, id: %s\n",
                    linenum,
                    person_arry[linenum].name,
                    person_arry[linenum].address,
                    person_arry[linenum].Id);
                linenum++;
                i=0;
                break;
            default:
                line[i]=ch;
                i++;
            }
        }

    }   
    return 0;
}

struct person insert_into_struct(char line[]){
    int i,j=0;

    // now we have to declare a temp structre to hold the seperated values
    struct person p;

    //now split the values one by one.
    //first copy the name from line[] into p.name
    for(i=0; line[i]!=',';i++, j++){
        p.name[j]=line[i];
    }
    i++;
    p.name[j]='\0';
    //printf("name=%s\n", p.name);

    //second copy the address in line[] to p.address[]
    for( j=0 ; line[i]!=',';i++, j++){
        p.address[j]=line[i];
    }
    i++;
    p.address[j]='\0';
    //printf("address=%s\n", p.address);

    // Erroneous line:
    //third copy the id in line[] to p.id[]
    for( j=0 ; line[i]!='\0';i++, j++){    
        p.Id[j]=line[i];
    }
    p.Id[j]='\0';
    //printf("Id=%s\n", p.Id);

    return(p);
}

Answer 1

将此函数添加到您的代码中以将字符串转换为数字(atoi 函数):

   int atoi(char* str)
    {
        if(!str)
            printf("Enter valid string");

        int number = 0;
        char* p = str;

        while((*p >= '0') && (*p <= '9'))
        {
            number = number * 10 + (*p - '0');
            p++;
        } 
        return number;
    }

然后像这样实现:

而不是

 for( j=0 ; line[i]!='\0';i++, j++){
        p.Id[j]=line[i];
    }

写:

p.Id = atoi(line);