gpt4 book ai didi

c - Bash 没有这样的文件或目录错误(缓存模拟器)

转载 作者:行者123 更新时间:2023-11-30 17:27:46 24 4
gpt4 key购买 nike

我正在设计一个缓存模拟器来计算未命中、命中、驱逐的数量。我尝试使用以下命令编译我的程序,它运行良好,没有任何错误,

Program
#include <stdlib.h>
#include <stdio.h>
#include <getopt.h>
#include <strings.h>
#include <limits.h>

//#include "cachelab.h"

/* Always use a 64-bit variable to hold memory addresses*/
typedef unsigned long long int mem_addr_t;

/* a struct that groups cache parameters together */
typedef struct
{
int s; /* 2**s cache sets */
int b; /* cacheline block size 2**b bytes */
int E; /* number of cachelines per set */
int S; /* number of sets, derived from S = 2**s */
int B; /* cacheline block size (bytes), derived from B = 2**b */
} cache_param_t;

int verbosity;

/* printUsage - Print usage info */
void printUsage( char *argv[] )
{
printf( "Usage: %s [-hv] -s <num> -E <num> -b <num> -t <file>\n", argv[0] );
printf( "Options:\n" );
printf( " -h Print this help message.\n" );
printf( " -v Optional verbose flag.\n" );
printf( " -s <num> Number of set index bits.\n" );
printf( " -E <num> Number of lines per set.\n" );
printf( " -b <num> Number of block offset bits.\n" );
printf( " -t <file> Trace file.\n" );
printf( "\nExamples:\n" );
printf( " %s -s 4 -E 1 -b 4 -t traces/yi.trace\n", argv[0] );
printf( " %s -v -s 8 -E 2 -b 4 -t traces/yi.trace\n", argv[0] );
exit( 0 );
}

void printSummary( int hit_count, int miss_count, int eviction_count )
{
printf( "hits: %d misses: %d evictions: %d\n", hit_count, miss_count, eviction_count );
}

int main( int argc, char **argv )
{
cache_param_t par;

bzero( &par, sizeof ( par ) );

char *trace_file;
char c;

while ( ( c = getopt( argc, argv, "s:E:b:t:vh" ) ) != -1 )
{
switch ( c )
{
case 's':
par.s = atoi( optarg );
break;
case 'E':
par.E = atoi( optarg );
break;
case 'b':
par.b = atoi( optarg );
break;
case 't':
trace_file = optarg;
break;
case 'v':
verbosity = 1;
break;
case 'h':
printUsage( argv );
exit( 0 );
default:
printUsage( argv );
exit( 1 );
}
}

if ( par.s == 0 || par.E == 0 || par.b == 0 || trace_file == NULL )
{
printf( "%s: Missing required command line argument\n", argv[0] );
printUsage( argv );
exit( 1 );
}

/* TODO: Compute S and B based on information passed in */

//Compute S and B, 2^s and 2^b respectively
par.S = ( 1 << par.s );
par.B = ( 1 << par.b );

/* TODO: Initialize a cache */

//Structure for a line
typedef struct
{
int valid;
mem_addr_t tag;
int timestamp;
} line_st;

//Structure for a set; a pointer to an array of lines
typedef struct
{
line_st *lines;
} cache_set;

//Structure for a cache; a pointer to an array of sets
typedef struct
{
cache_set *sets;
} cache_t;

//allocate space for sets and for lines
cache_t cache;
int i;

cache.sets = malloc( par.S * sizeof ( cache_set ) );
for (i = 0; i < par.S; i++ )
{
cache.sets[i].lines = malloc( sizeof ( line_st ) * par.E );
}

//counters
int hit_count = 0;
int miss_count = 0;
int eviction_count = 0;

/* TODO: Run the trace simulation */

char act; //L,S,M
int size; //size read in from file
int TSTAMP = 0; //value for LRU
int empty = -1; //index of empty space
int H = 0; //is there a hit
int E = 0; //is there an eviction
int e;
mem_addr_t addr;

//open the file and read it in
FILE *traceFile = fopen( trace_file, "r" );

if ( traceFile != NULL )
{
while ( fscanf( traceFile, " %c %llx,%d", &act, &addr, &size ) == 3 )
{
int toEvict = 0; //keeps track of what to evict
if ( act != 'I' )
{
//calculate address tag and set index
mem_addr_t addr_tag = addr >> ( par.s + par.b );
int tag_size = ( 64 - ( par.s + par.b ) );
unsigned long long temp = addr << ( tag_size );
unsigned long long setid = temp >> ( tag_size + par.b );
cache_set set = cache.sets[setid];
int low = INT_MAX; // CHANGED, also added #include <limits.h>

for (e = 0; e < par.E; e++ ) {
if ( set.lines[e].valid == 1 ) {
// CHANGED ORDER: look for hit before eviction candidates
if ( set.lines[e].tag == addr_tag ) {
hit_count++;
H = 1;
set.lines[e].timestamp = TSTAMP;
TSTAMP++;
}
// CHANGED WHOLE ELSE: look for oldest for eviction.
else if ( set.lines[e].timestamp < low ) {
low = set.lines[e].timestamp;
toEvict = e;
}
}
// CHANGED: if we haven't yet found an empty, mark one that we found.
else if( empty == -1 ) {
empty = e;
}
}

//if we have a miss
if ( H != 1 )
{
miss_count++;
//if we have an empty line
if ( empty > -1 )
{
set.lines[empty].valid = 1;
set.lines[empty].tag = addr_tag;
set.lines[empty].timestamp = TSTAMP;
TSTAMP++;
}
//if the set is full we need to evict
else if ( empty < 0 )
{
E = 1;
set.lines[toEvict].tag = addr_tag;
set.lines[toEvict].timestamp = TSTAMP;
TSTAMP++; // CHANGED: increment TSTAMP here too
eviction_count++;
}
}
//if the instruction is M, we will always get a hit
if ( act == 'M' )
{
hit_count++;
}
//if the -v flag is set print out all debug information
if ( verbosity == 1 )
{
printf( "%c ", act );
printf( "%llx,%d", addr, size );
if ( H == 1 )
{
printf( "Hit " );
}
else if ( H != 1 )
{
printf( "Miss " );
}
if ( E == 1 )
{
printf( "Eviction " );
}
// CHANGED: don't print Hit again since 'M' is always going to print Hit above.
printf( "\n" );
}
empty = -1;
H = 0;
E = 0;
}
}
}

/* TODO: Clean up cache resources */

/* TODO: Print out real results */
printSummary( hit_count, miss_count, eviction_count );
void printSummary(int hits, int misses, int evictions)
{
printf("hits:%d misses:%d evictions:%d\n", hits, misses, evictions);
FILE* output_fp = fopen(".csim_results", "w");
fprintf(output_fp, "%d %d %d\n", hits, misses, evictions);
fclose(output_fp);
}
return 0;
}


Compile command
gcc -Wall hello.c -o hello.out -lm

But when i tried to execute the code i am getting the following error :

error while running the program
bash: ./hello:No such file or directory

The command which i used to run is as follows

Run command
./hello [hv] -s 5 -E 1 -b 5 -t traces/trans.trace

Expected output
Hits 231 Misses 7 Evictions 0

我很确定我在执行程序时设置的路径是正确的,但我无法找到遇到此问题的解决方案?帮帮我!!

最佳答案

您使用 gcc -Wall hello.c -o hello.out -lm 进行编译,因此您希望执行 ./hello.out

如果您想使用 ./hello 运行,请使用以下行进行编译:

gcc -Wall hello.c -o hello -lm

关于c - Bash 没有这样的文件或目录错误(缓存模拟器),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/26268878/

24 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com