连续 "undefined reference to..."

Question

我正在开发一个程序，但我不断收到“对‘dosell’的 undefined reference ”，我不太明白发生了什么。这是函数的声明:

void dosell(int *cash, int *numchips);

函数的使用:

choice = menu();

// Execute the appropriate choice.
if (choice == 1) {
    dobuy(&cash, &numchips);
}
else if (choice == 2) {
    dosell(&cash, &numchips);
}

以及函数本身:

void dosell(int *cash, int *numchips) {

   int numsell;

   // Determine the number of chips to be sold.
   printf("How many chips do you want to sell?\n");
   scanf("%d", &numsell);

   // Print out the error message if this is too much.
   if (numsell > *numchips)
       printf("Sorry, you do not have that many chips. No chips sold.\n");

   // Execute the transaction.
    else {
       (*cash) += sellchips(numsell);
       (*numchips) -= numsell;
}}}

Answer 1

将函数声明放在文件的开头，即在主函数之前、包含和定义之后:

void dosell(int *cash, int *numchips) ;