c - SDL2/C 中放慢矩形速度

Question

你好，我尝试在我的程序中拥有真正的重力，因此当我不按键时，较小的矩形应该减慢速度。这是我尝试过的代码，但什么也没发生(在这方面):

 #include <stdio.h>
#include <SDL2/SDL.h>

int main()
{

  //Request successful execute
  if(SDL_Init(SDL_INIT_EVERYTHING)!=0)
  {
    printf("fehler");
    return 1;
  }

  //create window 800x600
  SDL_Window *win;
  win = SDL_CreateWindow("test",100,100,800,600,SDL_WINDOW_SHOWN);

  //create renderwindow with vysnc enabled
  SDL_Renderer *ren = SDL_CreateRenderer(win, -1, SDL_RENDERER_ACCELERATED | SDL_RENDERER_PRESENTVSYNC);

  if(ren==NULL)
  {
    printf("Fehler");
    SDL_Quit();
    return 1;
  }


  //boolean data type not supported
  int gameRunning = 1;

 SDL_Event event;
 const Uint8 *keystate=SDL_GetKeyboardState(NULL);

//create rectangle which is the whole window
 SDL_Rect rect={
    0,0,800,600
  };
  //smaller rectangle 
  SDL_Rect rect2={
    10,10,50,50
  };

  float v_x = 0;
  float v_y = 0;
  float speedup = 1.f;

//while loop to hold the window opened
  while (gameRunning)
  {
    if (SDL_PollEvent(&event))//close the window 
    {
      if (event.type == SDL_QUIT)
      {
          gameRunning = 0;
      }
    }
    //color of the first rectangle(red)
    SDL_SetRenderDrawColor(ren, 255,0,0,255);
    SDL_RenderClear(ren);
    SDL_RenderFillRect( ren, &rect );

    //second rectangle (blue)
    SDL_SetRenderDrawColor(ren, 0,0,255,255);
    SDL_RenderFillRect( ren, &rect2 );
    //change/update the render
    SDL_RenderPresent(ren);


    if(keystate[SDL_SCANCODE_LSHIFT])
    {
      if (keystate[SDL_SCANCODE_A] ) 
      {
        v_x -= speedup;
      }
      if (keystate[SDL_SCANCODE_D] ) 
      {
        v_x += speedup;
      }
      if (keystate[SDL_SCANCODE_S] ) 
      {
        v_y += speedup;
      }
      if (keystate[SDL_SCANCODE_W] ) 
      {
        v_y -= speedup;
      }
    }
    else if(SDL_KEYDOWN)
    {
      if (keystate[SDL_SCANCODE_A] ) 
      {
        v_x -= 0.1f;
      }

      if (keystate[SDL_SCANCODE_D] ) 
      {
        v_x += 0.1f;
      }

      if (keystate[SDL_SCANCODE_S] ) 
      {
        v_y += 0.1f;
      }

      if (keystate[SDL_SCANCODE_W] ) 
      {
        v_y -= 0.1f;
      }
    }
     else
     {  //make slower(doesnt work)


           v_x= -v_x * 1.f;
           v_y= -v_y * 1.f;
            if(v_x<0.005f || v_y<0.005f)
            {
              v_x=0;
              v_y=0;
            }

     }

    rect2.x += v_x;
    rect2.y += v_y;

    if(rect2.x<0)
      v_x= -v_x * 0.8f;
    else if(rect2.x>=(800-50))
      v_x= -v_x * 0.8f;

    if(rect2.y<0)
      v_y= -v_y * 0.8f;
    else if(rect2.y>=(600-50))
      v_y= -v_y * 0.8f;


  }
  //give heap free
  SDL_DestroyRenderer(ren);
  SDL_DestroyWindow(win);

  SDL_Quit();
    return 0;
}

我的想法是每帧覆盖重力 v_x 和 v_y。有什么问题？当矩形碰到边界时，v_x/v_y 变得更慢，这是相同的代码。PS:我使用C和lib SDL2。

当前代码部分:

else if(event.type==SDL_KEYDOWN)
{
  if (keystate[SDL_SCANCODE_A] ) 
  {
    v_x -= 0.1f;
  }

  if (keystate[SDL_SCANCODE_D] ) 
  {
    v_x += 0.1f;
  }

  if (keystate[SDL_SCANCODE_S] ) 
  {
    v_y += 0.1f;
  }

  if (keystate[SDL_SCANCODE_W] ) 
  {
    v_y -= 0.1f;
  }
}

 //make slower(doesnt work)

     else
     {
       v_x-=0.0000005;
       v_y-=0.0000005;
        if(v_x<0.000005f || v_y<0.000005f)
        {
          v_x=0;
          v_y=0;
        }
     }

Answer 1

你的第一个问题是:

else if (SDL_KEYDOWN)

这始终是正确的，因此从未到达 else 分支。这可能应该是:

else if (event.type == SDL_KEYDOWN)

下一个问题是你的速度减慢代码(注意:空格是免费的，并且更容易阅读):

v_x -= 0.0000005;
v_y -= 0.0000005;

if (v_x < 0.000005f || v_y < 0.000005f)
{
    v_x = 0;
    v_y = 0;
}

这仅在您的初始速度为正时才有效。如果任一速度为负，它会立即将两者设置为 0。有几种方法可以正确执行此操作，但最简单的就是显式检查:

const float MIN_SPEED = 0.000005f; // Add to top of function or as a global

...

if (v_x > MIN_SPEED)
   v_x -= MIN_SPEED;
else if (v_x < -MIN_SPEED)
   v_x += MIN_SPEED;
else
   v_x = 0;

并对 v_y 进行相同的检查。