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c - 读入文件并在c中创建双链表

转载 作者:行者123 更新时间:2023-11-30 17:25:29 25 4
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所以我是 C 编码新手,在使用以下代码创建链接列表时遇到问题。我一直遇到的问题是 fscanf 每次读入内容时都会更改变量。所以我的头指针值不断变化。有没有办法来解决这个问题?谢谢!

经过一番讨论,我意识到这是因为结构体中的助记符是一个指针,所以 head 的助记符会发生变化,因为它只是指向指针。有没有办法在不改变结构本身的情况下解决这个问题? (意思是将助记符留在struct Instr中作为指针)

void linkTypeInstr(struct InstrType *it, char *c, FILE *mfp){
int count = 0;
char type[2], mnemonic[11];
uint32_t uid = 0, pretty = 0;
struct Instr *head = NULL;
struct Instr *ptr = NULL;
/*read through the file in format*/
while(fscanf(mfp, "%s %u %s %u ", type, &uid, mnemonic, &pretty) != NULL){
if(head != NULL)
printf("head: %s\n", head -> mnemonic);
/*check if is the match type*/
if(*type == *c){
/*make a new struct instr for the item want to add*/
struct Instr *temp = malloc(sizeof(struct Instr));
memset(temp, 0, sizeof(struct Instr));
temp -> uid = uid;
temp -> pretty = pretty;
temp -> mnemonic = mnemonic;
temp -> next = NULL;
temp -> prev = NULL;
printf("temp: %s\n", temp -> mnemonic);
printf("count: %d\n", count);
/*check if list is empty, set ptr to head*/
if(count == 0){
head = temp;
count++;
}
/*if list is not empty, find the place to put the item in alphabetical order*/
else{
ptr = head;
printf("head: %s\n", head -> mnemonic);
while(ptr != NULL){
/*if temp should come after ptr in the order*/
if(strcmp(ptr -> mnemonic, temp -> mnemonic) < 0){
if(ptr -> next == NULL){
ptr -> next = temp;
temp -> prev = ptr;
count++;
ptr = NULL;
}
else if(strcmp(temp -> mnemonic, ptr -> next -> mnemonic) < 0){
temp -> next = ptr -> next;
ptr -> next -> prev = temp;
ptr -> next = temp;
temp -> prev = ptr;
count++;
ptr = NULL;
}
else
/*if should be after ptr -> next*/
ptr = ptr -> next;
}
/*if temp should come before ptr in the order*/
else if(strcmp(temp -> mnemonic, ptr -> mnemonic) < 0){
if(ptr -> prev == NULL){
ptr -> prev = temp;
temp -> next = ptr;
head = temp;
count++;
ptr = NULL;
}
else if(strcmp(ptr -> prev -> mnemonic, temp -> mnemonic) < 0){
ptr -> prev -> next = temp;
temp -> prev = ptr -> prev;
ptr -> prev = temp;
temp -> next = ptr;
count++;
ptr = NULL;
}
else
/*if should be before ptr -> prev*/
ptr = ptr -> prev;
}
}
}
}
}
it -> count = count;
it -> head = head;
}


struct Instr {
uint32_t uid; /* Unique identification bits */
uint32_t pretty; /* The type of pretty print format this Instr is */
char *mnemonic; /* The human readable mnemonic */
struct Instr *next; /* Pointer for doubly linked list */
struct Instr *prev; /* Pointer for doubly linked list */
};

struct InstrType {
char type; /* Should be R, I, or J */
size_t count; /* Length of Instr list */
struct InstrType *next; /* Points to the next InstrType node */
struct InstrType *prev; /* Points to the next InstrType node */
struct Instr *head; /* Points to the first Instr node of this type */
};

我试图读取的文件看起来像这样:

r 00000020 add 3
r 00000021 addu 3
r 00000022 sub 3
r 00000023 subu 3
r 00000018 mult 2
r 00000019 multu 2
r 0000001a div 1
r 0000001b divu 1
r 00000010 mfhi 0
r 00000011 mthi 0
r 00000012 mflo 0
r 00000013 mtlo 0
r 00000000 sll 8
r 00000002 srl 8
r 00000003 sra 8
r 00000004 sllv 3
r 00000006 srlv 3
r 00000007 srav 3
r 00000024 and 3
r 00000025 or 3
r 00000026 xor 3
r 00000027 nor 3
r 0000002a slt 3
r 0000002b sltu 3
r 00000008 jr 0
r 00000009 jalr 2
r 0000000c syscall 5
i 20000000 addi 2
i 24000000 addiu 2
i 3c000000 lui 2
i 28000000 slti 2
i 2c000000 sltiu 2
i 30000000 andi 2
i 34000000 ori 2
i 38000000 xori 2
i 80000000 lb 4
i 84000000 lh 4
i 88000000 lwl 4
i 8c000000 lw 4
i 90000000 lbu 4
i 98000000 lwr 4
i a0000000 sb 4
i a4000000 sh 4
i a8000000 swl 4

当我运行此命令时,结果总是将我的 head ptr 更改为创建的新临时值:

temp: add
count: 0
head: addu
temp: addu
count: 1
head: addu
...

调用该函数的代码如下所示:

int main(int argc, char *argv[]){
int c;
int iFlag = 0, oFlag = 0;
char mFileName[256] = "instruction_mapping.txt";
char oFileName[256];
char iFileName[256];
extern char *optarg;
FILE *mfp, *ifp, *ofp;

/*create three struct instrtype nodes*/
struct InstrType *itR = malloc(sizeof(struct InstrType));
struct InstrType *itI = malloc(sizeof(struct InstrType));
struct InstrType *itJ = malloc(sizeof(struct InstrType));

memset(itR, 0, sizeof(struct InstrType));
memset(itI, 0, sizeof(struct InstrType));
memset(itJ, 0, sizeof(struct InstrType));

/*link the struct instrtype together*/
if(itR != NULL && itI != NULL && itJ != NULL){
itR -> prev = NULL;
itR -> next = itI;
itI -> prev = itR;
itI -> next = itJ;
itJ -> prev = itI;
itJ -> next = NULL;
}

/*set up instrtypes*/
itR -> type = 'R';
itI -> type = 'I';
itJ -> type = 'J';

/* parse arguments */
while ((c = getopt(argc, argv, "m:i:o:h")) != -1){
switch(c){
case 'h':
USAGE(argv[0]);
return EXIT_SUCCESS;
case 'm':
strcpy(mFileName, optarg);
break;
case 'i':
iFlag = 1;
strcpy(iFileName, optarg);
break;
case 'o':
oFlag = 1;
strcpy(oFileName, optarg);
break;
default:
USAGE(argv[0]);
return EXIT_FAILURE;
}
}

/*check -i and -o must be in argv*/
if(iFlag == 1 && oFlag == 1){
mfp = fopen(mFileName, "r");
if(mfp == NULL){
printf("Cannot open instruction mapping file\n");
EXIT_FAILURE;
}
printf("mapping file: %s\n", mFileName);
ifp = fopen(iFileName, "r");
if(ifp == NULL){
printf("Cannot open input file\n");
EXIT_FAILURE;
}
printf("input file: %s\n", iFileName);
ofp = fopen(oFileName, "w");
if(ofp == NULL){
printf("Error creating or writing file\n");
EXIT_FAILURE;
}
printf("output file: %s\n", oFileName);

/* make linked lists of instr in R, I, J instrtype */
linkTypeInstr(itR, "r", mfp);
linkTypeInstr(itI, "i", mfp);
linkTypeInstr(itJ, "j", mfp);


if(mfp != NULL)
fclose(mfp);
if(ifp != NULL)
fclose(ifp);
if(ofp != NULL)
fclose(ofp);
}
else{
printf("Must have both input and output files\n");
return EXIT_FAILURE;
}
free(itR);
free(itI);
free(itJ);
return EXIT_SUCCESS;
}

最佳答案

你的问题是这一行:

temp -> 助记符 = 助记符;

事实上 temp->mnemonic 是一个指针,这意味着它将始终指向助记符数组中相同的 11 个字符。由于 head 是从 temp 分配的,因此 head->mnemonic 将指向相同的 11 个字符,这些字符将在下次调用 fscanf 时被覆盖。

解决方案是更改您的

结构指令{
uint32_t uid;/* 唯一标识位 */
uint32_t 漂亮;/* 该 Instr 的 pretty-print 格式类型 */
char *助记符;/* 人类可读的助记符 */
结构指令 *下一个;/* 双向链表指针 */
结构指令 *prev;/* 双向链表指针 */
};

结构指令{
uint32_t uid;/* 唯一标识位 */
uint32_t 漂亮;/* 该 Instr 的 pretty-print 格式类型 */
字符助记符[11];/* 人类可读的助记符 */
结构指令 *下一个;/* 双向链表指针 */
结构指令 *prev;/* 双向链表指针 */
};

并用 strncpy 对其进行赋值:

strncpy(temp -> 助记符, 助记符, 11);

关于c - 读入文件并在c中创建双链表,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/27070817/

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