创建 BlockType 结构的单链表

Question

我正在尝试使用这 3 个 typedef struct(人物、统计数据和车辆)创建一个单链表。

#include <stdio.h>
#include <stdlib.h>
#include <string.h>


typedef struct{
  char name[22];
  char city[10];
  int yearBorn;
}  person;


typedef struct{
  int height[8];
  double weight[18];
  }  Stats;

typedef struct{
 char car[16];
 int horsepower[20];
}  vehicle;


typedef struct node {
   person   *p; 
   Stats *stat;
   vehicle *hp;
   struct node *next;
}NODE;

typedef struct {
   NODE *head, *tail;
}SLL;


int main(){
void insert(SLL *list, person p, vehicle hp,  Stats stat){


a = (NODE *)malloc(sizeof(p));
b = (NODE *)malloc(sizeof(hp));
c = (NODE *)malloc(sizeof(stat));

if(list->head == NULL){
 return NULL;
}
list -> head -> next = a;
list -> head -> next-> next  = b;
list -> head -> next-> next -> next = c;
list -> tail = c;


}




return 0;
}

我不断收到 a、b 和 c 的错误，提示错误:“a”未声明(在此函数中首次使用)。我只是想知道我这样做是否正确，以及这个错误意味着什么。我真的很感激任何有关我的代码的见解。谢谢。

Answer 1

问题就在这里

int main(){
    void insert(SLL *list, person p, vehicle hp,  Stats stat){


    a = (NODE *)malloc(sizeof(p));
    b = (NODE *)malloc(sizeof(hp));
    c = (NODE *)malloc(sizeof(stat));

      if(list->head == NULL){
         return NULL;
      }
    list -> head -> next = a;
    list -> head -> next-> next  = b;
    list -> head -> next-> next -> next = c;
    list -> tail = c;
    }

return 0;
}

如何在另一个函数中定义一个函数？!!