c - 我正在尝试使用 malloc 函数为数组分配内存，但值未正确扫描。谁能解释一下吗？

Question

所以我被要求编写一个程序来测试用户输入的整数序列是否是回文(向后读取与向前读取相同)。我不知道如何动态分配内存以便输入可以具有可变长度。在代码中，您可以看到用户输入了序列中的元素数量 n。但在编译期间，当输入 n 个整数时，什么也没有发生。代码有什么问题吗？请尽可能详细地解释一下，如果您知道任何好的引用资料，请分享!!我正在努力处理指针和数组。

#include <stdio.h>
#include <stdlib.h>
int main ()
{
    int i, n, x; 
    int* intarray;
    printf("\nHow many integers are there?: \n");
    scanf("d", &n);
    intarray = (int*)malloc(n * sizeof(int));
    printf("\nPlease enter the values:\n");
    for (i = 0; i < n; i++)
    {
        scanf("%d", &intarray[i]);
    }
    n = n - 1;
    x = n / 2;
    for (i = 0; i <= x; i++)
    {
        if (intarray[i] != intarray[n - i])
        {
            printf("\nThis is not a palindrome\n");
            return;
        }

        if (i = x)
        {
            printf("\nThis is a palindrome\n");
        }
    }
return;
}

Answer 1

#include <stdio.h>
#include <stdlib.h>
int main ()
{
 int i, n, x; 
 int* intarray;
 printf("\nHow many integers are there?: \n");
 scanf("%d", &n); // and as mentioned by all above type specifier % is missing in %d (for integer type)
 intarray = (int*)malloc(n * sizeof(int));
 printf("\nPlease enter the values:\n");
 for (i = 0; i < n; i++)
 {
    scanf("%d", &intarray[i]);
 }
 n = n - 1;
 x = n / 2;
 for (i = 0; i <= x; i++)
 { 
    if (intarray[i] != intarray[n - i])
    {
        printf("\nThis is not a palindrome\n");
        return;
    }

    if (i = x)
    {
        printf("\nThis is a palindrome\n");
    }
 }
return 0; // as your main()'s return type is int, you should should return an integer value
}