C 编程获取用户信息

Question

这是我第一次使用 C 我需要询问用户一些信息才能输入

 #include <stdio.h>
#include <stdlib.h>

int main(void) {
    int age;
    int i;
    char last_name[20];
    char first_name[20];
    double wight;
    char gender[1];


    printf("Enter your age: ");
    scanf("%d", &age);
    printf("Enter your last name: ");
    fgets(last_name, 18, stdin);
        i = strlen(last_name)-1;
        if( last_name[ i ] == '\n')
            last_name[i] = '\0';

    printf("Enter your first name: ");
    fgets(first_name, 18, stdin);
            i = strlen(first_name)-1;
            if( first_name[ i ] == '\n')
                first_name[i] = '\0';

    printf("Enter your wight: ");
    scanf("%lf", &wight);
    printf("Enter your gender m/f: ");
    gets(gender);

    printf("You entered %s successfully\n ", first_name);
    return EXIT_SUCCESS;
}

如果我运行该程序 输入您的年龄:23 输入您的姓氏: 输入您的名字:

我没有给我输入姓氏的机会 它跳到下一行

我使用的是eclipse ide

Answer 1

试试这个:

#include <stdio.h>
#include <stdlib.h>

int main(void) {
    int age;
    int i;
    char last_name[20];
    char first_name[20];
    double wight;
    char gender[1];


    printf("Enter your age: ");
    scanf("%d", &age);
    printf("Enter your last name: ");
    __fpurge ( stdin );
    fgets(last_name, 18, stdin);
        i = strlen(last_name)-1;
        if( last_name[ i ] == '\n')
            last_name[i] = '\0';

    printf("Enter your first name: ");
    fgets(first_name, 18, stdin);
            i = strlen(first_name)-1;
            if( first_name[ i ] == '\n')
                first_name[i] = '\0';

    printf("Enter your wight: ");
    scanf("%lf", &wight);
    printf("Enter your gender m/f: ");
    __fpurge ( stdin );
    gets(gender);

    printf("You entered %s successfully\n ", first_name);
    return EXIT_SUCCESS;
}