c - "lvalue required as left operand of assignment"

Question

查看了涉及相同错误的其他问题，但不太明白为什么我会收到错误。

我正在尝试将方程分配给同名函数内的变量？

我对此很陌生，所以如果有人可以向我解释为什么会发生这种情况，那就太棒了。

倒数第五行是我收到错误的地方

#define DAYS_PER_WEEK 7

#define THURSDAY 0
#define FRIDAY   1
#define SATURDAY 2
#define SUNDAY   3
#define MONDAY   4
#define TUESDAY  5
#define WEDNESDAY 6

#define TRUE 1
#define FALSE 0
#define DAYS_PER_WEEK 7

int dayOfWeek (int doomsday, int leapYear, int month, int day);

int main (int argc, char *argv[]) {

   dayOfWeek(SUNDAY, FALSE, 1, 10);

   return EXIT_SUCCESS;
}

int dayOfWeek (int doomsday, int leapYear, int month, int day) {
   if (month == 1) {
      int doomsDate = 4;
      dayOfWeek = (day + doomsDate)/DAYS_PER_WEEK);
      printf ("The day of the week is: =%d\n",dayOfWeek);
   }
   return dayOfWeek;
 }

所以在 @Gopi 解释了为什么我将函数更改为这个之后

int dayOfWeek (int doomsday, int leapYear, int month, int day) {
   if (month == 1) {
      int doomsDate = 4;
      int dayNum = (day + doomsDate)/DAYS_PER_WEEK;
      printf ("The day of the week is: =%d\n",dayNum);
   }
   return dayOfWeek;
}

我需要满足以下断言:

assert (dayOfWeek (SUNDAY, FALSE, 1, 10) == SATURDAY); 

我该怎么做...

Answer 1

dayOfWeek = (day + doomsDate)/DAYS_PER_WEEK);

dayOfWeek 是一个函数名称，因此它不能是可分配的左值。

I'm trying to assign an equation to a variable within a function of the same name?

函数 dayOfWeek() 中没有变量 dayOfWeek。