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c - 使用 libcurl 构建项目在 Linux 下不起作用

转载 作者:行者123 更新时间:2023-11-30 17:16:52 26 4
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我正在尝试在 Linux 下的 Eclipse Juno 中用 C 语言构建一个小项目。当我包含 libcurl 库时,我认为链接器总是抛出错误“找不到 -lcurl”。我知道互联网上有很多帖子,但没有什么真正有帮助。整体看起来是这样的:

Building target: c_template
Invoking: GCC C Linker
/usr/local/oecore-i686-arm/sysroots/i686-oesdk-linux/usr/bin/armv7a-vfp-neon-oe-linux-gnueabi/arm-oe-linux-gnueabi-gcc -L/usr/lib --sysroot=/usr/local/oecore-i686-arm/sysroots/armv7a-vfp-neon-oe-linux-gnueabi -o "c_template" ./src/atCommand.o ./src/charDevice.o ./src/curl.o ./src/debug.o ./src/linux_prototype.o ./src/output.o ./src/simStatus.o ./src/urc.o ./src/wwan.o -lpthread -lcurl
from <command-line>:0:
/home/ubuntu/Documents/eCall/hwell_06/workspace_hwell_06/c_template/inc/defs.h:87:10: warning: type defaults to 'int' in declaration of 'BOOL' [-Wimplicit-int]
/home/ubuntu/Documents/eCall/hwell_06/workspace_hwell_06/c_template/inc/atCommand.h:56:12: warning: 'atCommandsHandler' defined but not used [-Wunused-variable]
/home/ubuntu/Documents/eCall/hwell_06/workspace_hwell_06/c_template/inc/debug.h:60:12: warning: 'deviceHandler' defined but not used [-Wunused-variable]
/usr/local/oecore-i686-arm/sysroots/i686-oesdk-linux/usr/libexec/armv7a-vfp-neon-oe-linux-gnueabi/gcc/arm-oe-linux-gnueabi/4.6.3/ld: warning: skipping incompatible /usr/lib/libpthread.so while searching for pthread
/usr/local/oecore-i686-arm/sysroots/i686-oesdk-linux/usr/libexec/armv7a-vfp-neon-oe-linux-gnueabi/gcc/arm-oe-linux-gnueabi/4.6.3/ld: warning: skipping incompatible /usr/lib/libcurl.so while searching for curl
/usr/local/oecore-i686-arm/sysroots/i686-oesdk-linux/usr/libexec/armv7a-vfp-neon-oe-linux-gnueabi/gcc/arm-oe-linux-gnueabi/4.6.3/ld: error: cannot find -lcurl
/usr/local/oecore-i686-arm/sysroots/i686-oesdk-linux/usr/libexec/armv7a-vfp-neon-oe-linux-gnueabi/gcc/arm-oe-linux-gnueabi/4.6.3/ld: warning: skipping incompatible /usr/lib/libc.so while searching for c
../src/curl.c:66: error: undefined reference to 'curl_global_init'
../src/curl.c:69: error: undefined reference to 'curl_easy_init'
../src/curl.c:72: error: undefined reference to 'curl_slist_append'
../src/curl.c:73: error: undefined reference to 'curl_slist_append'
../src/curl.c:76: error: undefined reference to 'curl_easy_setopt'
../src/curl.c:79: error: undefined reference to 'curl_easy_setopt'
../src/curl.c:82: error: undefined reference to 'curl_easy_setopt'
../src/curl.c:85: error: undefined reference to 'curl_easy_setopt'
../src/curl.c:98: error: undefined reference to 'curl_easy_perform'
../src/curl.c:101: error: undefined reference to 'curl_easy_strerror'
../src/curl.c:105: error: undefined reference to 'curl_slist_free_all'
../src/curl.c:108: error: undefined reference to 'curl_easy_cleanup'
../src/curl.c:112: error: undefined reference to 'curl_global_cleanup'
collect2: ld returned 1 exit status
make: *** [c_template] Error 1

我已经为链接器设置了库的路径:对于库搜索路径 (-L):/usr/lib对于库(-l):curl

我的命令行模式如下所示:

${COMMAND} ${FLAGS} ${OUTPUT_FLAG} ${OUTPUT_PREFIX} ${OUTPUT} ${INPUTS}

谁能帮帮我。那就太好了。

非常感谢

最佳答案

您正在交叉编译适用于 ARM 的 c_template,因此您需要在交叉编译环境中安装适用于 ARM 的 libcurl。现在它找到了您的 i686 主机的 libcurl 并且无法使用它,如下所示:

/usr/local/oecore-i686-arm/sysroots/i686-oesdk-linux/usr/libexec/armv7a-vfp-neon-oe-linux-gnueabi/gcc/arm-oe-linux-gnueabi/4.6.3/ld: warning: skipping incompatible /usr/lib/libcurl.so while searching for curl

因此,首先在编译环境中为您的目标平台编译/安装libcurl,并确保您的编译器可以找到它。

关于c - 使用 libcurl 构建项目在 Linux 下不起作用,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/29532798/

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