c - 在循环之间移动数组

Question

好吧，这是我项目的一部分，我遇到了麻烦。我需要能够选择一个类别，然后让它指向一个单词列表，然后需要这些单词用于各种用途。

到目前为止，我已将我的单词分为不同的类别，并且它们能够嵌入到我的二维数组中。但是，我现在需要根据用户输入检查这些单词，看看它们是否匹配。

我已经创建了一个函数来检查 2 个数组是否匹配，但是在将单词输入到函数中时遇到问题。

这是我的话的排序方式。

        printf("\n\n------------------------------");
        printf("\n1. Animals");
        printf("\n2. Colors");
        printf("\n3. Planets");
        printf("\n4. Weekdays");
        printf("\n------------------------------");


        int valid = 0;
        while(valid == 0)
        {
                    printf("\n\nYour selection: ");
                    int catagory;
                    scanf("%d", &catagory);

                    if(catagory == 1)
                    {
                                char word[] = "dog";
                                char word2[] = "cat";
                                char word3[] = "chicken";
                                char word4[] = "mouse";
                                char word5[] = "lion";
                                char word6[] = "rabbit";
                                char word7[] = "pig";                                  
                                horizontal(myArray, word);
                                horizontal(myArray, word2);
                                diagonal(myArray, word3);
                                diagonal(myArray, word4);
                                vertical(myArray, word5);
                                vertical(myArray, word6);
                                horizontal(myArray, word7);  
                                valid++;


                    }
                    else if(catagory == 2)
                    {
                                char word[] = "red";
                                char word2[] = "blue";
                                char word3[] = "yellow";
                                char word4[] = "brown";
                                char word5[] = "pink";
                                char word6[] = "green";
                                char word7[] = "black";
                                horizontal(myArray, word);
                                horizontal(myArray, word2);
                                diagonal(myArray, word3);
                                diagonal(myArray, word4);
                                vertical(myArray, word5);
                                vertical(myArray, word6);
                                horizontal(myArray, word7);  
                                valid++;

                    }
                    else if(catagory == 3)
                    {
                                char word[] = "earth";
                                char word2[] = "neptune";
                                char word3[] = "venus";
                                char word4[] = "mars";
                                char word5[] = "jupiter";
                                char word6[] = "saturn";
                                char word7[] = "pluto";
                                horizontal(myArray, word);
                                horizontal(myArray, word2);
                                diagonal(myArray, word3);
                                diagonal(myArray, word4);
                                vertical(myArray, word5);
                                vertical(myArray, word6);
                                horizontal(myArray, word7); 
                                valid++;

                    }
                    else if(catagory == 4)
                    {
                                char word[] = "monday";
                                char word2[] = "tuesday";
                                char word3[] = "wednesday";
                                char word4[] = "thursday";
                                char word5[] = "friday";
                                char word6[] = "saturday";
                                char word7[] = "saturn";
                                horizontal(myArray, word);
                                horizontal(myArray, word2);
                                diagonal(myArray, word3);
                                diagonal(myArray, word4);
                                vertical(myArray, word5);
                                vertical(myArray, word6);
                                horizontal(myArray, word7);  
                                valid++;

                    }
                    else if(catagory > 4)
                    {
                                printf("\n\nInvalid input. Please select again.\n");                                    
                    }
                    else if(catagory < 1)
                    {
                                printf("\n\nInvalid input. Please select again.\n");
                    }
        }

下面我现在再次需要这些词:

        clock_t start = clock(), diff;
        int match = 0;
        int correct = 0;
        print_array(myArray);
        printf("\nPlease type any words that you can find");
        while (correct != 7)
        {                 
              printf("\n: ");
              char word2[256];
              fgets(word2,256,stdin);

              match = checker("word from category",word2);
              if(match == 1)
              {
                  correct++;
                  printf("\nWeldone you found a match!");
              }

        }


        diff = clock() - start;

        int msec = diff * 1000 / CLOCKS_PER_SEC;
        printf("Time taken %d seconds %d milliseconds\n", msec/1000,                       msec%1000);

如您所见，我的数组超出了范围。谁能给我一个解决方案吗？

Answer 1

也许定义一个全局三维数组可能会有所帮助:

char words[4][8][];

words[0] = {"dog", "cat", "chicken", "mouse", "lion", "rabbit", "pig"};
//etc...

(you can of course define it in one line)

然后您可以使用以下方式访问它:

words[catagory][<WORD>]

(最后一个维度是单词本身)

或者我误解了你的问题？然后我需要知道你的水平函数和对角函数以及整个代码正在做什么。