- html - 出于某种原因,IE8 对我的 Sass 文件中继承的 html5 CSS 不友好?
- JMeter 在响应断言中使用 span 标签的问题
- html - 在 :hover and :active? 上具有不同效果的 CSS 动画
- html - 相对于居中的 html 内容固定的 CSS 重复背景?
我的 C89 编程任务的一部分涉及将文本文件的内容(一行中包含未知数量的单词)读取到链接列表中。单词之间用空格分隔。我想,输入 strtok。
我的函数尚未 100% 完成,但它能够正确地从缓冲区中抓取单词(之前使用 fgetc 逐个字符读取)并将它们粘贴到链表节点的“单词”字段中,并且我只是在继续之前检查是否可以再次打印出这些文字。
例如如果:这里是用户文件中的一些单词\0
是缓冲区的内容,那么输出如下所示:
head->word = here
head->word = are
head->word = some
head->word = words
...
这符合预期。然而,有时运行时的输出有点奇怪,通常表现为单词从开头或结尾或两者都缺少一个或两个字符。有时,似乎一个单词被切成两半,其中一部分跨两行输出。这是来自同一个可执行文件!在过去的一个小时里,我读了其他几篇文章,但一无所获,完全被难住了 - 我想我最好先解决这个问题,然后再继续,以防我的整个方法需要改变。
我的代码如下,对于这个令人沮丧的事情,任何帮助都会受到赞赏......我想是时候去拿另一个红牛了。
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include "nodestruct.h"
char** readUserfile(char** userFilename, int* numUserwords)
{
/* Open user file for reading */
FILE* userPtr = fopen(*userFilename, "r");
char ch = (char)fgetc(userPtr); /* 'ch' temporarily stores input taken by fgetc() */
int length = 0; /* Eventually the length of the file's line, +1 for a null terminator */
char **userArray = NULL;
/* Creating a temporary buffer to store the contents of the user file. The buffer is allowed to grow
until it holds the contents of the file, as we are told the user file has all it's words on one line,
separated by whitespace, however we do not know the total number of words preventing us from using
fgets() to read in the line (unless we make an arbitrary decision on a very big 'size' argument) */
int BUFFER_SIZE = 128;
char* buffer = (char*)malloc( sizeof(char) * BUFFER_SIZE );
/* Delimiter for call to strtok() below: the whitespace that separates words in the user file */
char delim = ' ';
const char* delimPtr = &delim;
/* String to catch return value of strtok() so we can check if non-null (i.e. returns a word) or null
(end the linked list at this word) */
char* strtokReturn;
/* Read user file: */
/* While still contents to be read */
while(ch != EOF)
{
if(length != BUFFER_SIZE)
{
buffer[length] = ch;
length++;
}
else /* Buffer is full, so realloc, doubling the size each time */
{
BUFFER_SIZE *= 2;
buffer = realloc(buffer, BUFFER_SIZE);
buffer[length] = ch;
length++;
}
/* Read the next character. If EOF reached, the while loop condition will stop the read */
ch = (char)fgetc(userPtr);
}
/* Trim the buffer to only contain the information that was read + '\0' */
buffer = realloc(buffer, (sizeof(char) * (length+1)) );
buffer[length] = '\0';
/* Just a note in case the user file was empty */
if(length == 0)
{
printf("Note: no words found in user file.\n");
}
/* Create a linked list containing all the words read by the above method */
Node* head = (Node*)malloc(sizeof(Node));
/* Enter the first word into the list - strtok() is used here to begin breaking up the contents of the
buffer read previously into separate strings (words). The delimiter is the whitespace character ' ' */
strtokReturn = strtok(buffer, delimPtr);
strcpy(head->word, strtokReturn);
printf("head->word = <<%s>>\n", head->word);
head->next = NULL;
strtokReturn = strtok(NULL, delimPtr);
strcpy(head->word, strtokReturn);
printf("head->word = <<%s>>\n", head->word);
head->next = NULL;
strtokReturn = strtok(NULL, delimPtr);
strcpy(head->word, strtokReturn);
printf("head->word = <<%s>>\n", head->word);
head->next = NULL;
strtokReturn = strtok(NULL, delimPtr);
strcpy(head->word, strtokReturn);
printf("head->word = <<%s>>\n", head->word);
head->next = NULL;
strtokReturn = strtok(NULL, delimPtr);
strcpy(head->word, strtokReturn);
printf("head->word = <<%s>>\n", head->word);
head->next = NULL;
strtokReturn = strtok(NULL, delimPtr);
strcpy(head->word, strtokReturn);
printf("head->word = <<%s>>\n", head->word);
head->next = NULL;
strtokReturn = strtok(NULL, delimPtr);
strcpy(head->word, strtokReturn);
printf("head->word = <<%s>>\n", head->word);
head->next = NULL;
strtokReturn = strtok(NULL, delimPtr);
strcpy(head->word, strtokReturn);
printf("head->word = <<%s>>\n", head->word);
head->next = NULL;
strtokReturn = strtok(NULL, delimPtr);
strcpy(head->word, strtokReturn);
printf("head->word = <<%s>>\n", head->word);
head->next = NULL;
strtokReturn = strtok(NULL, delimPtr);
strcpy(head->word, strtokReturn);
printf("head->word = <<%s>>\n", head->word);
head->next = NULL;
strtokReturn = strtok(NULL, delimPtr);
strcpy(head->word, strtokReturn);
printf("head->word = <<%s>>\n", head->word);
head->next = NULL;
free(head);
head = NULL;
free(buffer);
buffer = NULL;
fclose(userPtr);
return userArray;
}/* End readUserfile() */
输出(请原谅长度,但为了充分披露):
[Danyal@DanCentos assign]$ ./wordfixr userfile.txt
Spellrc opened/read successfully.
Dictionary file opened successfully.
Dictionary read successfully.
head->word = <<here>>
head->word = <<are>>
head->word = <<some>>
head->word = <<words>>
head->word = <<in>>
head->word = <<the>>
head->word = <<user>>
head->word = <<file>>
head->word = <<and>>
head->word = <<the>>
head->word = <<whole>>
[Danyal@DanCentos assign]$ ./wordfixr userfile.txt
Spellrc opened/read successfully.
Dictionary file opened successfully.
Dictionary read successfully.
head->word = <<h>>
head->word = <<r>>
head->word = <<ar>>
head->word = <<som>>
head->word = <<words>>
head->word = <<in>>
head->word = <<th>>
head->word = <<us>>
head->word = <<r>>
head->word = <<fil>>
head->word = <<and>>
[Danyal@DanCentos assign]$ ./wordfixr userfile.txt
Spellrc opened/read successfully.
Dictionary file opened successfully.
Dictionary read successfully.
head->word = <<here>>
head->word = <<are>>
head->word = <<some>>
head->word = <<words>>
head->word = <<in>>
head->word = <<the>>
head->word = <<user>>
head->word = <<file>>
head->word = <<and>>
head->word = <<the>>
head->word = <<whole>>
[Danyal@DanCentos assign]$ ./wordfixr userfile.txt
Spellrc opened/read successfully.
Dictionary file opened successfully.
Dictionary read successfully.
head->word = <<here>>
head->word = <<are>>
head->word = <<some>>
head->word = <<words>>
head->word = <<in>>
head->word = <<the>>
head->word = <<user>>
head->word = <<file>>
head->word = <<and>>
head->word = <<the>>
head->word = <<whole>>
[Danyal@DanCentos assign]$ ./wordfixr userfile.txt
Spellrc opened/read successfully.
Dictionary file opened successfully.
Dictionary read successfully.
head->word = <<here>>
head->word = <<are>>
head->word = <<some>>
head->word = <<words>>
head->word = <<in>>
head->word = <<the>>
head->word = <<user>>
head->word = <<file>>
head->word = <<and>>
head->word = <<the>>
head->word = <<whole>>
[Danyal@DanCentos assign]$ ./wordfixr userfile.txt
Spellrc opened/read successfully.
Dictionary file opened successfully.
Dictionary read successfully.
head->word = <<here>>
head->word = <<are>>
head->word = <<some>>
head->word = <<words>>
head->word = <<in>>
head->word = <<the>>
head->word = <<user>>
head->word = <<file>>
head->word = <<and>>
head->word = <<the>>
head->word = <<whole>>
[Danyal@DanCentos assign]$ ./wordfixr userfile.txt
Spellrc opened/read successfully.
Dictionary file opened successfully.
Dictionary read successfully.
head->word = <<here>>
head->word = <<are>>
head->word = <<some>>
head->word = <<words>>
head->word = <<in>>
head->word = <<the>>
head->word = <<user>>
head->word = <<file>>
head->word = <<and>>
head->word = <<the>>
head->word = <<whole>>
[Danyal@DanCentos assign]$ ./wordfixr userfile.txt
Spellrc opened/read successfully.
Dictionary file opened successfully.
Dictionary read successfully.
head->word = <<h>>
head->word = <<r>>
head->word = <<ar>>
head->word = <<som>>
head->word = <<words>>
head->word = <<in>>
head->word = <<th>>
head->word = <<us>>
head->word = <<r>>
head->word = <<fil>>
head->word = <<and>>
[Danyal@DanCentos assign]$ ./wordfixr userfile.txt
Spellrc opened/read successfully.
Dictionary file opened successfully.
Dictionary read successfully.
head->word = <<here>>
head->word = <<are>>
head->word = <<some>>
head->word = <<words>>
head->word = <<in>>
head->word = <<the>>
head->word = <<user>>
head->word = <<file>>
head->word = <<and>>
head->word = <<the>>
head->word = <<whole>>
[Danyal@DanCentos assign]$ ./wordfixr userfile.txt
Spellrc opened/read successfully.
Dictionary file opened successfully.
Dictionary read successfully.
head->word = <<here>>
head->word = <<are>>
head->word = <<some>>
head->word = <<words>>
head->word = <<in>>
head->word = <<the>>
head->word = <<user>>
head->word = <<file>>
head->word = <<and>>
head->word = <<the>>
head->word = <<whole>>
[Danyal@DanCentos assign]$ ./wordfixr userfile.txt
Spellrc opened/read successfully.
Dictionary file opened successfully.
Dictionary read successfully.
head->word = <<here>>
head->word = <<are>>
head->word = <<some>>
head->word = <<words>>
head->word = <<in>>
head->word = <<the>>
head->word = <<user>>
head->word = <<file>>
head->word = <<and>>
head->word = <<the>>
head->word = <<whole>>
[Danyal@DanCentos assign]$ ./wordfixr userfile.txt
Spellrc opened/read successfully.
Dictionary file opened successfully.
Dictionary read successfully.
head->word = <<here>>
head->word = <<are>>
head->word = <<some>>
head->word = <<words>>
head->word = <<in>>
head->word = <<the>>
head->word = <<user>>
head->word = <<file>>
head->word = <<and>>
head->word = <<the>>
head->word = <<whole>>
[Danyal@DanCentos assign]$ ./wordfixr userfile.txt
Spellrc opened/read successfully.
Dictionary file opened successfully.
Dictionary read successfully.
head->word = <<here>>
head->word = <<are>>
head->word = <<some>>
head->word = <<words>>
head->word = <<in>>
head->word = <<the>>
head->word = <<user>>
head->word = <<file>>
head->word = <<and>>
head->word = <<the>>
head->word = <<whole>>
[Danyal@DanCentos assign]$ ./wordfixr userfile.txt
Spellrc opened/read successfully.
Dictionary file opened successfully.
Dictionary read successfully.
head->word = <<here>>
head->word = <<are>>
head->word = <<some>>
head->word = <<wor>>
head->word = <<s>>
head->word = <<in>>
head->word = <<the>>
head->word = <<user>>
head->word = <<file>>
head->word = <<an>>
head->word = <<the>>
请注意,我更改了 printf 语句,将打印的字符串封装在一些括号中,以确保没有在另一个线程中看到的不可见字符,但正如您所看到的,仅打印了单词。
再次提前感谢您的帮助,我真的很感激,并且非常感激生活在像堆栈溢出这样的地方免费存在的时代。
最佳答案
strtok 的第二个参数应该是一个以 null 结尾的字符串。strtok
认为该字符串的任何元素都是有效的分隔符。如果您只需要一个分隔符,请使用长度为 1 的字符串:
strtokReturn = strtok(buffer, " ");
如果没有 '\0'
来终止 delimPtr
,strtok
就会查看紧随 delim< 的字节
。显然,它有时会在 '\0'
字符之前找到 'e'
字符,并最终将 'e'
视为另一个分隔符。
关于c - 每次运行程序时 strtok() 的输出都会给出不同的行为,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/33334536/
我正在使用 OUTFILE 命令,但由于权限问题和安全风险,我想将 shell 的输出转储到文件中,但出现了一些错误。我试过的 #This is a simple shell to connect t
我刚刚开始学习 Java,我想克服在尝试为这个“问题”创建 Java 程序时出现的障碍。这是我必须创建一个程序来解决的问题: Tandy 喜欢分发糖果,但只有 n 颗糖果。对于她给第 i 个糖果的人,
你好,我想知道我是否可以得到一些帮助来解决我在 C++ 中打印出 vector 内容的问题 我试图以特定顺序在一个或两个函数调用中输出一个类的所有变量。但是我在遍历 vector 时收到一个奇怪的错误
我正在将 intellij (2019.1.1) 用于 java gradle (5.4.1) 项目,并使用 lombok (1.18.6) 来自动生成代码。 Intellij 将生成的源放在 out
编辑:在与 guest271314 交流后,我意识到问题的措辞(在我的问题正文中)可能具有误导性。我保留了旧版本并更好地改写了新版本 背景: 从远程服务器获取 JSON 时,响应 header 包含一
我的问题可能有点令人困惑。我遇到的问题是我正在使用来自 Java 的 StoredProcedureCall 调用过程,例如: StoredProcedureCall call = new Store
在我使用的一些IDL中,我注意到在方法中标记返回值有2个约定-[in, out]和[out, retval]。 当存在多个返回值时,似乎使用了[in, out],例如: HRESULT MyMetho
当我查看 gar -h 的帮助输出时,它告诉我: [...] gar: supported targets: elf64-x86-64 elf32-i386 a.out-i386-linux [...
我想循环遍历一个列表,并以 HTML 格式打印其中的一部分,以代码格式打印其中的一部分。所以更准确地说:我想产生与这相同的输出 1 is a great number 2 is a great
我有下面的tekton管道,并尝试在Google Cloud上运行。集群角色绑定。集群角色。该服务帐户具有以下权限。。例外。不确定需要为服务帐户设置什么权限。
当尝试从 make 过滤非常长的输出以获取特定警告或错误消息时,第一个想法是这样的: $ make | grep -i 'warning: someone set up us the bomb' 然而
我正在创建一个抽象工具类,该类对另一组外部类(不受我控制)进行操作。外部类在某些接口(interface)点概念上相似,但访问它们相似属性的语法不同。它们还具有不同的语法来应用工具操作的结果。我创建了
这个问题已经有答案了: What do numbers starting with 0 mean in python? (9 个回答) 已关闭 7 年前。 在我的代码中使用按位与运算符 (&) 时,我
我写了这段代码来解析输入文件中的行输入格式:电影 ID 可以有多个条目,所以我们应该计算平均值输出:**没有重复(这是问题所在) import re f = open("ratings2.txt",
我需要处理超过 1000 万个光谱数据集。数据结构如下:大约有 1000 个 .fits(.fits 是某种数据存储格式)文件,每个文件包含大约 600-1000 个光谱,其中每个光谱中有大约 450
我编写了一个简单的 C 程序,它读取一个文件并生成一个包含每个单词及其出现频率的表格。 该程序有效,我已经能够在 Linux 上运行的终端中获得显示的输出,但是,我不确定如何获得生成的显示以生成包含词
很难说出这里要问什么。这个问题模棱两可、含糊不清、不完整、过于宽泛或夸夸其谈,无法以目前的形式得到合理的回答。如需帮助澄清此问题以便重新打开,visit the help center . 关闭 1
1.普通的输出: print(str)#str是任意一个字符串,数字··· 2.格式化输出: ?
我无法让 logstash 正常工作。 Basic logstash Example作品。但后来我与 Advanced Pipeline Example 作斗争.也许这也可能是 Elasticsear
这是我想要做的: 我想让用户给我的程序一些声音数据(通过麦克风输入),然后保持 250 毫秒,然后通过扬声器输出。 我已经使用 Java Sound API 做到了这一点。问题是它有点慢。从发出声音到
我是一名优秀的程序员,十分优秀!