c - 时间不正确，但代码似乎正确 :S (unexpected outcome)

Question

所以我试图构建一个程序来告诉你准确的时间(以年、日、小时和分钟为单位)。

我已经检查了我的代码，看起来没问题，结果接近正确，但并不完全正确，我在下面发布了我的代码:

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

void year_day(time_t seconds, float *yearsLPtr, float *dayLPtr){
    int yearS;
    float t_constant;//seconds per year

    t_constant = 365.2425*24*60*60; //seconds in a year (years to 4dp)
    *yearsLPtr =(seconds/t_constant);// years as float since 1970 1/1 00:00
    yearS=*yearsLPtr; //sending float to int
    *dayLPtr = (((seconds/t_constant) - yearS)*365.2425);//used exact number for years to neglext error
    *yearsLPtr+=1970; //adding 1970 to change in years to get current year
}

void hours_minutes(float dayL, float *hoursLPtr, float *minsLPtr){
    float t_constant;
    int dayS, minS;
    dayS=dayL;
    t_constant= 365.2425*24*60*60;
    *hoursLPtr= (dayL-dayS)*24;
    minS= *hoursLPtr;
    *minsLPtr= (((dayL-dayS)*24)-minS)*60;


}

void print_time (float yearsL, float dayL, float hoursL, float minsL){

    int constant, yearsS, dayS, hoursS, minsS;

    yearsS=yearsL; //converting from float back to int, couldve pointed to int straight away tho
    dayS=dayL;
    hoursS=hoursL;
    minsS=minsL;

    printf("Year: %i \t", yearsS);
    printf("Day: %i \t",dayS);
    printf("Hour: %i \t",hoursS);
    printf("Min: %i \t",minsS);

}


int main() {

    float yearsL, dayL, hoursL, minsL;

    time_t current_seconds; //time t like long/double for longer values

    current_seconds=time(NULL);

    year_day(current_seconds,&yearsL,&dayL);
    hours_minutes(dayL,&hoursL,&minsL);
    print_time(yearsL,dayL,hoursL,minsL);





getchar();

}

Answer 1

我发现的一个问题是您只使用了 time()。此函数不会返回您所在时区的时间。如果您需要您所在时区的时间，则需要使用 localtime() 来获取正确的时间。