c - 我们如何从c中的函数返回一个数组？

Question

这个问题已经有答案了:

Returning an array using C (8 个回答)

已关闭 7 年前。

我们如何从函数返回一个数组，我不知道该怎么做？？？有三辆车，每辆车在 parking 场最多停放 24 小时，我们必须通过创建一个评估成本的函数来找到每辆车的成本..??

#include <stdio.h>
#include <math.h>
#include <conio.h>
int calculateCharges(float hours[]);

int main() {
float hours[3];
int i;
for (i = 0; i <= 2; i++) {
    printf("Enter the hours you parked for car : %d\n", i + 1);     
    scanf_s("%f", &hours[i]);
}
hours[i] = calculateCharges(hours[]);

printf("%-10s%-10s%-10s\n", "Cars", "Hours", "Charge");
for (i = 0;i <= 2;i++) {
    printf("%-10d%-10.2f%-10.2f\n", i + 1, hours[i], calculateCharges(hours));
}

_getch();
return 0;
}

int calculateCharges(float hours[]) {

float cost[3];
int i;
for (i = 0; i <= 2; i++) {

    if (hours[i] <= 3) {          //if car parked for 3 or less hours it cost 2$
        cost[i] = 2;
    }
    else if (hours[i] > 3 && hours[i] < 24) { //if car parked for more than 3 or less then 24 hours it cost 0.5$for each extra hour$
        cost[i] = 2 + ((hours[i] - 3) / 2);
    }
    else if (hours[i] == 24) {   //if hours = 24 hours 10$
        cost[i] = 10;
    }
    else {
        cost[i] = 0;                //else its an error value zero cost
    }

    return cost[i];
}

}

Answer 1

您可以传入另一个数组来返回成本，而不是使其成为本地数组。你的方法看起来像这样:

int calculateCharges(float hours[], float costs[], int num) {
    ...
    for(i=0;i<num;i++) {
        ...
        costs[i] = 2;