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c++ - 将 libpcap 数据包数据从 const u_char* 复制到另一个 const u_char*

转载 作者:行者123 更新时间:2023-11-30 17:06:41 30 4
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我正在尝试将 const u_char* 深度复制到 c/++ 中的另一个 const u_char*。

我有以下代码 -

void packetHandler(u_char *userData, const struct pcap_pkthdr* pkthdr, const u_char* packet) 
{
if(packet!=NULL)
{
int length = strlen((char*)packet);
const u_char* newPacket = new u_char[length];
memcpy((u_char*)newPacket, packet, length);
cout<<"Packet - "<<packet<<endl;
cout<<"New Packet - "<<newPacket<<endl;
packets.push_back(newPacket);
//processPacket(packet);
}
}

但我认为它没有被正确复制,因为两个拷贝的操作结果是不同的。

数据必须采用 const u_char* 形式,如 pcap 循环方法签名所规定。

我正在使用[使用 tcpdump 获得的]类型的更大样本进行测试,其中每个数据包都按顺序读取,并且我收到一个指向它的 const u_char* 指针 -

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Host: www.amazon.com
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Host: fls-na.amazon.com
User-Agent: Mozilla/5.0 (X11; Ubuntu; Linux i686; rv:28.0) Gecko/20100101 Firefox/28.0
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Connection: keep-alive

我想做的是将 pcap 文件中的所有数据包加载到内存缓冲区中以进行高速测试,如果从文件中读取每个数据包,速度可能会很慢。

任何指点将不胜感激。

最佳答案

我能够找出我的问题。长度不对。我应该使用数据包 header 中的长度。不管怎样,我觉得使用 strlen 对于 unsigned char 来说不是正确的选择。

我用另一篇文章弄清楚了 - vector of packets in libpcap

关于c++ - 将 libpcap 数据包数据从 const u_char* 复制到另一个 const u_char*,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/34506933/

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