c - 用 C 语言打印位集

Question

所以，这是我的代码: http://pastebin.com/MejYmpvK

我正在尝试让输出显示此内容:

The BitSet is:
0000000001001010

Modified BitSet at index '14' = '1' is:
0010000001001010

The value at index '14' is:
1

Modified Bitset at index '14' = '0' is:
0000000001001010

The value at index '14' is:
0

但是，它给了我这个输出:

The BitSet is:
0000000001001010

Modified BitSet at index '14' = '1' is:
0010000001001010

The value at index '14' is:
0

Modified Bitset at index '14' = '0' is:
0000000001001010

The value at index '14' is:
0

除了显示方法之外，一切都工作正常。不确定这里发生了什么(整个代码位于上面的 Pastebin 链接中):

/* Returns the value of the bit at 'index' */
int bitValue(bitSet bs, int index){

    /* Shifts right to the passed index value */
    int value = ((bs & (int)pow(power, index)) >> index);

    return value;
}

Answer 1

设置该位后，您的主要功能不会更新该值。试试这个；

int main () {
    bitSet bits = makeBitSet();
    int value = bitValue(bits, 14);

    printf("The BitSet is: \n");
    displayBitSet(bits);
    printf("\n\nModified BitSet at index '14' = '1' is: \n");
    setBit(&bits, 14);
    displayBitSet(bits);
    printf("\n\nThe value at index '14' is: \n");
    value = bitValue(bits, 14);
    printf("%d", value);
    printf("\n\nModified BitSet at index '14' = '0' is: \n");
    clearBit(&bits, 14);
    displayBitSet(bits);
    printf("\n\nThe value at index '14' is: \n");
    value = bitValue(bits, 14);
    printf("%d\n", value);

    return (0);
}