c - 简单的猜谜游戏，允许用户在正确猜出随机数后再次玩？

Question

#include<stdio.h>
#include<stdio.h>
#include<stdlib.h>
#include<math.h>
#include<time.h>

int random_num;
void guessGame(int guessed_num){

    char answer;
if (guessed_num == random_num){
    printf("Correct! That's the number.\n");
    printf("Would you like to play again (y or n)?\n");
    scanf("%c", &answer);
    if (answer=='y')
        scanf("%d", &guessed_num);
        guessGame(guessed_num);
    if (answer=='n')
        return 0;


}
else
    if (guessed_num < random_num)
        printf("Too low. Guess again.\n");
    else
        printf("Too high. Guess again.\n");
}

int main(){

int guessed_num = 0;
srand(time(NULL));
random_num = rand() % 50 + 1;

printf("I have a number between 1-50.\n");
printf("Can you guess what it is?\n");
printf("Enter your initial guess.\n");

while(1){

    scanf("%d", &guessed_num);
    guessGame(guessed_num);
}

return 0;
}

因此，在用户找到正确的随机数后，我希望他们能够再次玩游戏(如果他们愿意)。我该如何让代码重新运行？我尝试在我的guessGame 函数中执行此操作，但我知道这是错误的。

Answer 1

由于我的英语不好，我会给你代码(根据你的修改)。

    #include<stdio.h>
    #include<stdio.h>
    #include<stdlib.h>
    #include<math.h>
    #include<time.h>

    int random_num;

    int guessGame(int guessed_num) {


        if (guessed_num == random_num) {
           printf("Correct! That's the number.\n");
           return 1;
        } else if (guessed_num < random_num) {
              printf("Too low. Guess again.\n");
              return 0;
           } else {
              printf("Too high. Guess again.\n");
             return 0;
        }
    }

    int main() {
    char loop;
    while (1) {
    int guessed_num = 0;
    srand(time(NULL));
    random_num = rand() % 50 + 1;
    printf("I have a number between 1-50.\n");
    printf("Can you guess what it is?\n");
    printf("Enter your initial guess.\n");
    while (1) {
        scanf("%d", &guessed_num);
        int returnValue = guessGame(guessed_num);
        if (returnValue == 1) {
            break;
        }
    }
    printf("You wanna do it again? ");
    getchar();
    scanf("%c", &loop);
    if (loop == 'n') {
        break;
    }
}
return 0;
}