c - 即使函数不是静态的，第二次运行也会出错

Question

我已经创建了一个建筑物的功能，现在在第二个建筑物上创建了两个建筑物，它由于某种原因跳过了一些参数......为什么？现在我检查了代码几次，我没有使用任何静态变量，所以它不应该这样做......那么为什么它会记住第二次运行的时间？

更新我按照所说的做了，但现在它只返回 false...任何帮助都会有所帮助

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
//defines
#define SIZE 30
#define Q_SIZE 4
#define TRUE 1
#define FALSE 0
struct shape
    {
    char name[SIZE];   /* name of the shape */
    int edgeNum;       /* number of edges */
    char sPol[Q_SIZE]; /* if the shape is a regular polygrom */
    };
int shapeMaker();
int main(void)
{
    int check;
    check = shapeMaker();
    if (check == TRUE)
{
    printf("the two shapes are equals!\n");
}
    else if (check == FALSE)
{
    printf("the two shapes are not equals!\n");
}
system("PAUSE");
return 0;
}

int shapeMaker()
{
struct shape firstShape;    
struct shape secondShape;

printf("please enter the first shape name: ");
fgets(secondShape.name, SIZE, stdin);
secondShape.name[strcspn(secondShape.name, "\n")] = 0;
printf("\nnow please enter the number of Edges: ");
scanf("%d", &secondShape.edgeNum);
printf("\nis the shape is regular polygom (yes/no)? ");
scanf("%s", secondShape.sPol);
getchar();
printf("\nplease enter the second  shape name: ");
fgets(secondShape.name, SIZE, stdin);
secondShape.name[strcspn(secondShape.name, "\n")] = 0;
printf("\nnow please enter the number of Edges: ");
scanf("%d", &secondShape.edgeNum);
printf("\nis the shape is regular polygom (yes/no)? ");
scanf("%s", secondShape.sPol);
if (firstShape.name == secondShape.name && firstShape.edgeNum ==      secondShape.edgeNum && firstShape.sPol == secondShape.sPol)
{
    return TRUE;
}
else
{
    return FALSE;
}
} 

Answer 1

在 shapeMaker 开头和 fgets 之后添加 fflush(stdin);