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c - C 中使用分隔符分割字符串

转载 作者:行者123 更新时间:2023-11-30 16:59:17 25 4
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如何在 C 编程语言中编写一个函数来拆分并返回带有分隔符的字符串数组?

char* str = "JAN,FEB,MAR,APR,MAY,JUN,JUL,AUG,SEP,OCT,NOV,DEC";
str_split(str,',');

最佳答案

您可以使用strtok()分割字符串的函数(并指定要使用的分隔符)。请注意,strtok() 将修改传递给它的字符串。如果其他地方需要原始字符串,请复制它并将该副本传递给 strtok()

编辑:

示例(请注意,它不处理连续的分隔符,例如“JAN,,,FEB,MAR”):

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <assert.h>

char** str_split(char* a_str, const char a_delim)
{
char** result = 0;
size_t count = 0;
char* tmp = a_str;
char* last_comma = 0;
char delim[2];
delim[0] = a_delim;
delim[1] = 0;

/* Count how many elements will be extracted. */
while (*tmp)
{
if (a_delim == *tmp)
{
count++;
last_comma = tmp;
}
tmp++;
}

/* Add space for trailing token. */
count += last_comma < (a_str + strlen(a_str) - 1);

/* Add space for terminating null string so caller
knows where the list of returned strings ends. */
count++;

result = malloc(sizeof(char*) * count);

if (result)
{
size_t idx = 0;
char* token = strtok(a_str, delim);

while (token)
{
assert(idx < count);
*(result + idx++) = strdup(token);
token = strtok(0, delim);
}
assert(idx == count - 1);
*(result + idx) = 0;
}

return result;
}

int main()
{
char months[] = "JAN,FEB,MAR,APR,MAY,JUN,JUL,AUG,SEP,OCT,NOV,DEC";
char** tokens;

printf("months=[%s]\n\n", months);

tokens = str_split(months, ',');

if (tokens)
{
int i;
for (i = 0; *(tokens + i); i++)
{
printf("month=[%s]\n", *(tokens + i));
free(*(tokens + i));
}
printf("\n");
free(tokens);
}

return 0;
}

输出:

$ ./main.exe
months=[JAN,FEB,MAR,APR,MAY,JUN,JUL,AUG,SEP,OCT,NOV,DEC]

month=[JAN]
month=[FEB]
month=[MAR]
month=[APR]
month=[MAY]
month=[JUN]
month=[JUL]
month=[AUG]
month=[SEP]
month=[OCT]
month=[NOV]
month=[DEC]

关于c - C 中使用分隔符分割字符串,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/38241518/

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