c - scanf函数在C编程中跳过for循环中的输入

Question

我使用结构方法编写了简单的代码，在该代码中，我使用 3 个学生的 for 循环将字符串(名称)作为输入。对于第一次迭代，for 循环中的每一行都按应有的方式工作...但是第二次迭代出现问题...在第二次迭代中 scanf 正在跳过字符串(名称)的输入...

我的代码如下:

#include<stdio.h>

struct student_data
{
    char name[5];
    int dsd;
    int dic;
    int total;  
};

void main()
{
    struct student_data s[3];


    int i;

    for(i = 0;i<3;i++)
    {
        printf("Enter Name of Student\n");
        scanf("%[^\n]",s[i].name);         // Problem occures here in     
                                       //  second iteration  

        printf("\nEnter marks of DSD\n");
        scanf("%d",&s[i].dsd);

        printf("Enter marks of DIC\n");
        scanf("%d",&s[i].dic);


        s[i].total = s[i].dsd+s[i].dic;     

    }

    printf("%-10s %7s %7s  %7s\n ","Name","DSD","DIC","Total");
    for(i=0;i<3;i++)
    {

       printf("%-10s %5d  %6d      %6d\n",s[i].name,s[i].dsd,s[i].dic,s[i].total);
}  

}

Answer 1

您的代码的主要问题是您定义了 student_data s[2]这是一个大小为 2 的数组，但在循环中，您正在循环 for (i=0; i<3; i++)这对于大小为 3 的数组有效。这个小修改将正常工作:

 int main()
{
struct student_data s[2];  // array of size 2


int i;

for(i=0; i<2; i++)      // i will have values 0 and 1 which is 2 (same as size of your array)
{
    printf("Enter Name of Student\n");
    scanf("%s", s[i].name);

    printf("\nEnter marks of DSD\n");
    scanf("%d", &s[i].dsd);

    printf("Enter marks of DIC\n");
    scanf("%d", &s[i].dic);

    s[i].total = s[i].dsd+s[i].dic;

}

    printf("%-10s %7s %7s  %7s\n ","Name","DSD","DIC","Total");

    for(i=0; i<2; i++)   // same mistake was repeated here
    {
        printf("%-10s %5d  %6d     %6d\n",s[i].name,s[i].dsd,s[i].dic,s[i].total);
    }
return 0;
}