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c - 如何在 GTK 应用程序(或 GTK 和控制台应用程序)之间共享内存?

转载 作者:行者123 更新时间:2023-11-30 16:56:59 24 4
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我正在尝试通信两个程序(在一个程序中我使用 GTK,在另一个程序中我使用 C 编程的标准 IO)。在两者中我都使用了 shmget。 shmat,...等,以传达它们。

但是我要完成这些工作却遇到了很多麻烦...两个程序都可以编译,但没有一个按照我的意图运行。

我真正想做的是将数据从服务器发送到控制客户端程序的客户端(在这个测试中只是在终端上打印数字),客户端程序将在收到来自服务器的信号后完成其执行。

不幸的是,我无法使用 GTK 做到这一点,但我几乎在控制台应用程序中做到了这一点,但是当它自动运行(没有用户交互)时,客户端会在 65516 次迭代后崩溃。在游戏程序中这可能是一个问题,但是对于某些应用程序,下面的代码可以令人满意地工作。

我的问题是:为什么在达到65516次交互(客户端程序上调用shmat函数)后会出现错误?

在我 future 的应用程序中,必须避免此错误,否则会使程序崩溃......

如何避免它并保持我的程序(客户端应用程序)无限期运行?

还有其他方法可以通过一个程序来控制另一个程序吗?哪一种可行或更实用?

文件smh-02.h

#define  NOT_READY  -1
#define FILLED 0
#define TAKEN 1

struct Memory
{
int status;
int data[4];
int dado; // I just add this data
};

文件 Console_server01.c

#include  <stdio.h>
#include <stdlib.h>
#include <sys/types.h>
#include <sys/ipc.h>
#include <sys/shm.h>

#include "shm-02.h"

#define RUN_WITH_USER // Coment this line to user interactivity
// Or uncoment it to run automactic test indefinitely until segmented fail

key_t ShmKEY;
int ShmID;
struct Memory *ShmPTR;

//---------------------------------------------------------------------
void send_data(int info)
{
while(ShmPTR->status != TAKEN);

ShmPTR->status = NOT_READY;
ShmPTR->dado = info;
ShmPTR->status = FILLED; //Server has informed client that the shared memory have been FILLED
}
//---------------------------------------------------------------------
//---------------------------------------------------------------------
int main(int argc, char *argv[])
{

int info;

ShmKEY = ftok(".", 'x');
ShmID = shmget(ShmKEY, sizeof(struct Memory), IPC_CREAT | 0666);

if (ShmID < 0)
{
printf("*** shmget error (server) ***\n");
exit(1);
}

ShmPTR = (struct Memory *) shmat(ShmID, NULL, 0);

if ((int) ShmPTR == -1)
{
printf("*** shmat error (server) ***\n");
exit(1);
}

send_data(55); // This will send some signal to the client establish connection

info = 1; //----- Value to RUN_REPEATLY ------

do
{
#ifdef RUN_WITH_USER //----------------------------------
printf("\n Type:");
printf("\n [1] To move to RIGHT");
printf("\n [2] To move to LEFT");
printf("\n [3] To move to QUIT");
printf("\n You choice is: ");
scanf("%d",&info);
#endif //----------------------------------
send_data(info);
}
while(info != 3);

shmdt((void *) ShmPTR); //Server has detached its shared memory...
shmctl(ShmID, IPC_RMID, NULL); //Server has removed its shared memory...

return 0;
}

文件 Console_client01.c

#include  <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <sys/types.h>
#include <sys/ipc.h>
#include <sys/shm.h>

#include "shm-02.h"

int main(void)
{
key_t ShmKEY;
int ShmID;
struct Memory *ShmPTR;
ShmKEY = ftok(".", 'x');

int i = 0;
int trigger = 0; // trigger locked
ShmID = shmget(ShmKEY, sizeof(struct Memory), 0666);

if (ShmID < 0)
{
printf("*** shmget error (client) ***\n");
exit (1); //Client exits
}

do{
ShmPTR = (struct Memory *) shmat(ShmID, NULL, 0);

if ( (ShmPTR->status == FILLED)&&(trigger == 0) )
{
ShmPTR->status = TAKEN;
trigger = 1; // trigger pulled
}

while (ShmPTR->status != FILLED)
{
printf("\nWaiting status = FILLED\t|\t");
switch(ShmPTR->status)
{
case -1:
printf("Current status = NOT_READY");
break;
case 0:
printf("Current status = FILLED");
break;
case 1:
printf("Current status = TAKEN");
break;
}
sleep(1); // Uncoment this line to better user interactivity
}

usleep(800); // Uncoment this line to better user interactivity
i++;
printf("\ni = %d --/// | dado = %d ", i, ShmPTR->dado);

if ((int) ShmPTR == -1)
{
printf("*** shmat error (client) ***\n");
exit(1); //Client exits
}
else
{
if (ShmPTR->dado == 55)
{
printf("\nConnection ESTABLISHED"); //Go to the LEFT
ShmPTR->status = TAKEN;
}

if (ShmPTR->dado == 3) // Exiting Program
{
ShmPTR->status = TAKEN; //Client has informed server data have been taken...
shmdt((void *) ShmPTR); //Client has detached its shared memory...
exit (0); //Client exits
}

if (ShmPTR->dado == 1)
{
printf("\n<--- move LEFT"); //Go to the LEFT
ShmPTR->status = TAKEN;
}

if (ShmPTR->dado == 2)
{
printf("\n---> move RIGHT"); // Go to the RIGHT
ShmPTR->status = TAKEN;
}

if ( (ShmPTR->dado != 1)||(ShmPTR->dado != 2) )
{
printf("\nIdle | dado = %d",ShmPTR->dado ); //Doing NOTHING
ShmPTR->status = TAKEN;
}
}

}while (1); // 'Infinite' loop
exit(0);
}

Running the programs_Picture

Error after 65516 interations_Picture

最佳答案

您不应该使用共享内存进行通信。它不是类型安全的并且很难正确编码。

你真正需要的是序列化。考虑使用JSON-RPC用于沟通。是的,它比原始内存操作慢得多,但更安全、更便携、更容易正常工作Some even use it for heavy and often loads, let alone occasional loads like GUI input.

关于c - 如何在 GTK 应用程序(或 GTK 和控制台应用程序)之间共享内存?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/39708616/

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