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c - 如何在c中创建一个双向链表

转载 作者:行者123 更新时间:2023-11-30 16:54:59 26 4
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我正在尝试制作一个循环链表来模拟旋转轮盘赌轮。我已经搜索了网络并在代码中运行了我的逻辑,但我似乎无法发现我的逻辑中的错误。我真正需要帮助的是了解如何使双向链表循环。预先感谢您的任何帮助。该程序的目标是生成一个随机数,然后使用该数字迭代循环双向链表。目前,当我运行程序时,会迭代到最后一个数字,然后重复该最后一个数字,剩余的迭代将不包含在随机数中。

/*
Roulette program
*/



#include <stdio.h>
#include <stdlib.h>
#include <time.h>

struct node{
int value;
struct node * next;
struct node * prev;
};


struct node * create_node( struct node *, int );
void print_forwards( struct node *, int );
void print_backwards( struct node * );
struct node * get_last_node( struct node * );


int main ( int argc, char * argv[] ) {

printf("Welcome to the game of Roulette!\n");

int rand_num;
int i;


srand( time(NULL) );
rand_num = rand() % 400 + 1;

printf("\nFowards Random #: %d\n", rand_num );
// Numbers in order on a European Roulette wheel.
//0-32-15-19-4-21-2-25-17-34-6-27-13-36-11-30-8-23-10-5-24-16-33-1-20-
//14-31-9-22-18-29-7-28-12-35-3-26

struct node * the_list = NULL;
the_list = create_node( the_list, 0 );
the_list = create_node( the_list, 32 );
the_list = create_node( the_list, 15 );
the_list = create_node( the_list, 19 );
the_list = create_node( the_list, 4 );
the_list = create_node( the_list, 21 );
the_list = create_node( the_list, 2 );
the_list = create_node( the_list, 25 );
the_list = create_node( the_list, 17 );
the_list = create_node( the_list, 34 );
the_list = create_node( the_list, 6 );
the_list = create_node( the_list, 27 );
the_list = create_node( the_list, 13 );
the_list = create_node( the_list, 36 );
the_list = create_node( the_list, 11 );
the_list = create_node( the_list, 30 );
the_list = create_node( the_list, 8 );
the_list = create_node( the_list, 23 );
the_list = create_node( the_list, 10 );
the_list = create_node( the_list, 5 );
the_list = create_node( the_list, 24 );
the_list = create_node( the_list, 16 );
the_list = create_node( the_list, 33 );
the_list = create_node( the_list, 1 );
the_list = create_node( the_list, 20 );
the_list = create_node( the_list, 14 );
the_list = create_node( the_list, 31 );
the_list = create_node( the_list, 9 );
the_list = create_node( the_list, 22 );
the_list = create_node( the_list, 18 );
the_list = create_node( the_list, 29 );
the_list = create_node( the_list, 7 );
the_list = create_node( the_list, 28 );
the_list = create_node( the_list, 12 );
the_list = create_node( the_list, 35 );
the_list = create_node( the_list, 3 );
the_list = create_node( the_list, 26 );



print_forwards( the_list, rand_num );
// print_backwards( the_list );

getchar();
return 0;
}

struct node * create_node( struct node * the_list, int new_value ){

// Create the new node and set it value.
// Also set the next and prev. pointers to NULL.
struct node * head = (struct node *)malloc( sizeof( struct node ) );
head->value = new_value;
head->next = head;
head->prev = head;

struct node * temp;
temp->prev = (struct node *)malloc( sizeof( struct node ) );
temp = temp->prev;
temp->prev = head;
head->next = temp;

// create the new node at the front of the list.
if( the_list ){
// Set the existing list's prev pointer
// to point to our new node.
the_list->prev = head;
}
// In any case, set our new node to the list.
// This will work fine if the list is empty
// because the "the_list" pointer is NULL.
head->next = the_list;
return head;

}


void print_backwards( struct node * the_list ){
printf( "\n-- Printing Backwards --\n" );
while( the_list ){
printf( "%d\n",
the_list->value
);
the_list = the_list->next;
}
}

void print_forwards( struct node * the_list, int rand_num ){
printf( "\n-- Printing Forwards --\n" );
int i;
struct node * end = get_last_node( the_list );
for( i = 0; i < rand_num; i++ ){
printf( "%d ",
end->value
);
end = end->prev;
}
}

struct node * get_last_node( struct node * the_list ){
while( the_list ){
if( the_list->next == NULL ){
break;
}else{
the_list = the_list->next;
}
}
return the_list;
}

最佳答案

警告:正如其他人所提到的,使用固定长度数组而不是循环列表可能更容易,并将索引包装到以数组大小为模的数组中。

但是,话虽如此,回答你的问题......

为了说明如何将双向链表转换为循环链表,我提供了这两种类型的函数。您可以通过在命令行上指定-c来选择循环。

我从你的代码开始,但我必须进行相当多的重组(例如一些错误修复和添加一些缺失的代码)才能使事情正常工作[请原谅无偿的风格清理]:

/*
Roulette program
*/

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

struct node {
int value;
struct node *next;
struct node *prev;
};

int circflg;
int opt_d;

struct node *create_node(struct node *, int);
void print_forwards(struct node *, int);
void print_backwards(struct node *);

// main -- main program
int
main(int argc,char **argv)
{
char *cp;

--argc;
++argv;

for (; argc > 0; --argc, ++argv) {
cp = *argv;
if (*cp != '-')
break;

switch (cp[1]) {
case 'c':
circflg = ! circflg;
break;

case 'd':
opt_d = ! opt_d;
break;

default:
break;
}
}

printf("Welcome to the game of Roulette!\n");

int rand_num;

srand(time(NULL));
rand_num = rand() % 400 + 1;
printf("\nFowards Random #: %d\n", rand_num);

// Numbers in order on a European Roulette wheel.
// 0-32-15-19-4-21-2-25-17-34-6-27-13-36-11-30-8-23-10-5-24-16-33-1-20-
// 14-31-9-22-18-29-7-28-12-35-3-26

struct node *the_list = NULL;

the_list = create_node(the_list, 0);
the_list = create_node(the_list, 32);
the_list = create_node(the_list, 15);
the_list = create_node(the_list, 19);
the_list = create_node(the_list, 4);
the_list = create_node(the_list, 21);
the_list = create_node(the_list, 2);
the_list = create_node(the_list, 25);
the_list = create_node(the_list, 17);
the_list = create_node(the_list, 34);
the_list = create_node(the_list, 6);
the_list = create_node(the_list, 27);
the_list = create_node(the_list, 13);
the_list = create_node(the_list, 36);
the_list = create_node(the_list, 11);
the_list = create_node(the_list, 30);
the_list = create_node(the_list, 8);
the_list = create_node(the_list, 23);
the_list = create_node(the_list, 10);
the_list = create_node(the_list, 5);
the_list = create_node(the_list, 24);
the_list = create_node(the_list, 16);
the_list = create_node(the_list, 33);
the_list = create_node(the_list, 1);
the_list = create_node(the_list, 20);
the_list = create_node(the_list, 14);
the_list = create_node(the_list, 31);
the_list = create_node(the_list, 9);
the_list = create_node(the_list, 22);
the_list = create_node(the_list, 18);
the_list = create_node(the_list, 29);
the_list = create_node(the_list, 7);
the_list = create_node(the_list, 28);
the_list = create_node(the_list, 12);
the_list = create_node(the_list, 35);
the_list = create_node(the_list, 3);
the_list = create_node(the_list, 26);

print_forwards(the_list, rand_num);
print_backwards(the_list);

//getchar();

return 0;
}

int
print_entry(int totlen,int val)
{
int curlen;
char buf[100];

curlen = sprintf(buf," %2d",val);

if ((totlen + curlen) > 78) {
printf("\n");
totlen = 0;
}

fputs(buf,stdout);
totlen += curlen;

return totlen;
}

struct node *
list_last_node(struct node *the_list)
{
struct node *cur;
struct node *end;

end = the_list;

for (cur = the_list; cur != NULL; cur = cur->next)
end = cur;

return end;
}

struct node *
list_create_node(struct node *the_list, int new_value)
{
struct node *prev;

// Create the new node and set it value.
struct node *temp = (struct node *) malloc(sizeof(struct node));

// set the new value
temp->value = new_value;

// create the new node at the front of the list.
if (the_list == NULL) {
the_list = temp;
temp->next = NULL;
temp->prev = NULL;
}

// append to end
else {
prev = list_last_node(the_list);
temp->next = NULL;
temp->prev = prev;
prev->next = temp;
}

return the_list;
}

void
list_print_backwards(struct node *the_list)
{
struct node *cur;
struct node *end;
struct node *prev;
int len;

printf("\n-- Printing Backwards --\n");

cur = list_last_node(the_list);

len = 0;

for (; cur != NULL; cur = prev) {
len = print_entry(len,cur->value);
prev = cur->prev;
}

printf("\n");
}

void
list_print_forwards(struct node *the_list, int rand_num)
{
int i;
struct node *cur;
struct node *next;
int len;

printf("\n-- Printing Forwards --\n");

len = 0;
i = 0;
for (cur = the_list; cur != NULL; cur = next, ++i) {
if (i >= rand_num)
break;

next = cur->next;

len = print_entry(len,cur->value);
}

printf("\n");
}

struct node *
circ_create_node(struct node *the_list, int new_value)
{
struct node *prev;

// Create the new node and set it value.
struct node *temp = (struct node *) malloc(sizeof(struct node));

// set the new value
temp->value = new_value;

do {
// create the new node at the front of the list.
if (the_list == NULL) {
the_list = temp;
temp->next = temp;
temp->prev = temp;
break;
}

// append to end
prev = the_list->prev;
temp->next = the_list;
temp->prev = prev;
prev->next = temp;

the_list->prev = temp;
} while (0);

return the_list;
}

void
circ_print_backwards(struct node *the_list)
{
struct node *cur;
struct node *prev;
int len;

printf("\n-- Printing Backwards --\n");

len = 0;
for (cur = the_list; cur != NULL; cur = prev) {
len = print_entry(len,cur->value);
prev = cur->prev;
if (prev == the_list)
break;
}

printf("\n");
}

void
circ_print_forwards(struct node *the_list, int rand_num)
{
int i;
struct node *cur;
struct node *next;
int len;

printf("\n-- Printing Forwards --\n");

i = 0;
len = 0;
for (cur = the_list; cur != NULL; cur = next, ++i) {
if (i >= rand_num)
break;

next = cur->next;

len = print_entry(len,cur->value);

if (next == the_list)
break;
}

printf("\n");
}

struct node *
create_node(struct node *the_list, int new_value)
{

if (circflg)
the_list = circ_create_node(the_list,new_value);
else
the_list = list_create_node(the_list,new_value);

if (opt_d) {
printf("create_node: added %d\n",new_value);
print_forwards(the_list,-1);
print_backwards(the_list);
}

return the_list;
}

void
print_backwards(struct node *the_list)
{

if (circflg)
circ_print_backwards(the_list);
else
list_print_backwards(the_list);
}

void
print_forwards(struct node *the_list,int rand_num)
{

if (circflg)
circ_print_forwards(the_list,rand_num);
else
list_print_forwards(the_list,rand_num);
}

关于c - 如何在c中创建一个双向链表,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/40429669/

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