c# - 设置从第三方对象序列化的 JSON 属性的顺序

Question

我正在将对象序列化为我不拥有其代码的 JSON(因此我无法在每个属性上设置 [JsonProperty(Order = x)] 属性)。

我还需要仅指定某些要序列化的属性。

以下代码有效，但我还需要指定属性的顺序。

public class DynamicContractResolver : Newtonsoft.Json.Serialization.CamelCasePropertyNamesContractResolver
{
    private IList<string> _propertiesToSerialize = null;

    public DynamicContractResolver(IList<string> propertiesToSerialize)
    {
        _propertiesToSerialize = propertiesToSerialize;
    }

    protected override IList<JsonProperty> CreateProperties(Type type, Newtonsoft.Json.MemberSerialization memberSerialization)
    {
        IList<JsonProperty> properties = base.CreateProperties(type, memberSerialization); //.OrderBy(p => p.Order).ToList();
        return properties.Where(p => _propertiesToSerialize.Contains(p.PropertyName)).ToList();
    }
}

//...

List<string> propertiesToSerialize = new List<string>(new string[]
{
    "name",
    "masterString",
    "cruiseMode",
    "account"
});

DynamicContractResolver contractResolver = new DynamicContractResolver(propertiesToSerialize);

string json = Newtonsoft.Json.JsonConvert.SerializeObject(_objToSerialize, Newtonsoft.Json.Formatting.Indented,
    new Newtonsoft.Json.JsonSerializerSettings { ContractResolver = contractResolver });

输出是:

{
  "masterString": "Provider...",
  "cruiseMode": 2,
  "account": "xxx\yyy",
  "name": "AdWorksName"
}

但我需要它是:

{
  "name": "AdWorksName",
  "masterString": "Provider...",
  "cruiseMode": 2,
  "account": "xxx\yyy",
}

Answer 1

尽管 JSON spec从技术上讲，将对象定义为“一组无序的名称/值对”，JSON.net 仍然允许您根据需要设置属性的顺序。在您的解析器中，您只需在每个 JsonProperty 上设置 Order 值，然后按相应的顺序返回它们。

protected override IList<JsonProperty> CreateProperties(Type type, Newtonsoft.Json.MemberSerialization memberSerialization)
{
    IList<JsonProperty> properties = base.CreateProperties(type, memberSerialization)
        .Where(p => _propertiesToSerialize.Contains(p.PropertyName)).ToList();

    foreach (JsonProperty prop in properties)
    {
        prop.Order = _propertiesToSerialize.IndexOf(prop.PropertyName) + 1;
    }

    return properties.OrderBy(p => p.Order).ToList();
}

工作演示:https://dotnetfiddle.net/OhfWHl