c - 如何在 C 中打开 .txt 文件并连续将方程应用于每一行

Question

我必须为大学编写一个代码，其中我必须读取一个包含三列的 .txt 文件:一天中的小时、太阳辐射、雨量计(毫米)，并根据以下内容连续将方程应用于每一行用户给出的信息。我设法构建了将方程应用于用户一次选择的单行的代码。我如何将该方程应用于每一行并同时显示它们？

我正在使用的 .txt 文件是:

0   -0.82   17.2
1   2386    14.4
2   1980    0.22
3   470 0.0
4   2731    0.2
5   1531    0.0
6   3084    0.4
7   2197    0.4
8   313 0.0
9   1428    0.0
10  47.01   0.0
11  138.8   0.0
12  328.4   0.0
13  431.2   0.4
14  419.6   0.2
15  447.8   0.8
16  572.2   0.2
17  801.5   0.0
18  849.1   0.0
19  561.1   0.0
20  376.6   0.0
21  122.9   0.0
22  -1.69   0.0
23  -1.46   0.0

我的代码如下(请原谅不完美的地方，我是编程初学者):

#include <stdio.h>

#define efi  0.83 //83% , standart solar cell eficiency

int h,a;


int potency (int x, int y, int z)
{
    return (x*y*z);
}

int hour[24], i=0;
float radiation[24], rain[24], energ,energk,pt,p,e,ep,ee;



int main()
{



   FILE *arq;

   arq = fopen("file2.txt", "r");
   if(arq == NULL) {
      printf("Error! unable to open file! \n");
      getchar();
   }
   else {
      printf("File open... \n");
      printf("Reading file...\n");
      while (!feof(arq)){
         fscanf(arq,"%d %f %f\n", &hour[i], &radiation[i], &rain[i]);
         i++;
      }
    printf("Type desired hour \n");
      scanf("%d", &h);
    printf("type board area m^2\n");
      scanf("%d", &a);
    printf("type maximum board pontency in WATTS/M^2\n");
      scanf("%f", &p);
      ep=p*efi; //Board potential after calculated its standart eficiency
    printf("Total eficiency of the board is %.2f %", ep);
    pt=  a*ep;
    printf("Total board potential is %.2f\n", pt);

        energ= (pt*radiacao[h]); // generated energy
        energk=(float)energ/1000; // generated energy in kw


      printf("At %d hoour, there is an average of %.2f KW/m^2 radiation\n %.2f mm of rain\n and the total energy produced by the board will be %.2f Kw \n ", hour[h], radiation[h], rain[h], energk);
      printf("\n\n\n press <enter> to finish");
      getchar();
   }
   fclose(arq);
}

Answer 1

 #include <stdio.h>

  #define efi  0.83 //83% , standart solar cell eficiency

  int h,a;


  int potency (int x, int y, int z)
  {
     return (x*y*z);
 }

 int hour[24], i=0;
 float radiation[24], rain[24], energ,energk,pt,p,e,ep,ee;



int main()
{



  FILE *arq;

  arq = fopen("file2.txt", "r");
  if(arq == NULL) {
     printf("Error! unable to open file! \n");
     getchar();
  }
  else {
     printf("File open... \n");
     printf("Reading file...\n");
     while (!feof(arq)){
        fscanf(arq,"%d %f %f\n", &hour[i], &radiation[i], &rain[i]);
        i++;
     }
     printf("type board area m^2\n");   
     scanf("%d", &a);
     printf("type maximum board pontency in WATTS/M^2\n");
     scanf("%f", &p);
     ep=p*efi; //Board potential after calculated its standart eficiency
     printf("Total eficiency of the board is %.2f %", ep);
     pt=  a*ep;
     printf("Total board potential is %.2f\n", pt);

     int i;
     for(i = 0; i < 24; i++)
     {
       energ= (pt*radiation[i]); // generated energy
       energk=(float)energ/1000; // generated energy in kw


       printf("At %d hoour, there is an average of %.2f KW/m^2 radiation\n %.2f mm of rain\n and the total energy produced by the board will be %.2f Kw \n ", i, radiation[i], rain[i], energk);

     }
     scanf("%d", &a);
  }
  fclose(arq);
}