c - 如何从字符串数组中仅获取所需的元素

Question

我有一个字符串数组，我只需要用户所需的元素。字符串数组如下:

 const char* string2[]={"•-","-•••", "-•-•","-••", "•", "••-•","--•","••••","••","•---","-•-","•-••",
                       "--","-•","---","•-•","--•-","•-•","•••","-","••-","•••-","•--","-••-",
                       "-•--","--••","•----","••---","•••--","••••-","•••••","-••••","--•••","---••",
                       "----•","-----"," "};

我创建了一个逻辑，从中我将能够获取用户所需的字符串数组的数量，但我无法获得正确的输出。问题是，例如我输入 Hello，我得到的数字如下:[8 5 12 12 15]

现在我希望输出为 string2[8]:••、string2[5]:••-• 等。

我需要做哪些改变才能让它发挥作用？

for(a[i]=0;a[i]<length;a[i++]){
        printf("%s\t",string2[i]);
    }

我已尝试使其正常工作，但无法提供帮助。

Answer 1

你可能想要这样的东西:

for(int i = 0; i < length; i++)
    printf("%s\t", string2[a[i]]);