二维数组上下文中的 C 指针

Question

这是一个工作程序，它有一个代表迷你棋盘的 8 x 8 数组。实际的棋盘是 4 x 4 的，并且在数组中填充了零。

// Chessboard representation
//
#include <stdio.h>

unsigned char uuboard[8][8]={
{1,1,1,1,1,1,1,1}, {1,1,1,1,1,1,1,1},
{1,1,0,0,0,0,1,1}, {1,1,0,0,0,0,1,1},   
{1,1,0,0,0,0,1,1}, {1,1,0,0,0,0,1,1},   
{1,1,1,1,1,1,1,1}, {1,1,1,1,1,1,1,1} };     

unsigned char *uboard[8]={uuboard[0]+2, uuboard[1]+2, uuboard[2]+2, uuboard[3]+2,
                          uuboard[4]+2, uuboard[5]+2, uuboard[6]+2, uuboard[7]+2};
unsigned char **board=uboard+2;

int main(void) {
    // Make a change to the board directly, using 2-D array
    uuboard[3][3] = 8;
    printf("Print the board by accessing the 2-D array directly\n");
    for (int i=0;i<8;i++) {
        for (int j=0;j<8;j++) {
            printf("%d", uuboard[i][j]);
        }
        printf("\n");
    }
    printf("Print again using pointers\n");
    for (int i=0; i<4; i++, printf("\n")) {
      for (int j=0; j<4; j++) {
          printf("%d", board[i][j]);
      }
    }
    printf("\n");   
    return 0;
}

最初的程序员似乎使用指针，因此他/她通过从 0 而不是 2 开始索引来到达实际的棋盘方格。这令人费解。 *uboard[8] 和 **board 如何完成这项工作？非常感谢任何答案或对答案的引用。

Answer 1

线路

unsigned char *uboard[8]={uuboard[0]+2, uuboard[1]+2, uuboard[2]+2, uuboard[3]+2, uuboard[4]+2, uuboard[5]+2, uuboard[6]+2, uuboard[7]+2};  

相当于

unsigned char *uboard[8]={&uuboard[0][2], &uuboard[1][2], &uuboard[2][2], &uuboard[3][2], &uuboard[4][2], &uuboard[5][2], &uuboard[6][2], &uuboard[7][2]};  

和

unsigned char **board=uboard+2;  

相当于

unsigned char **board = &uboard[0]+2; 
// or 
unsigned char **board = &uboard[2];