javascript - js提交后检查按钮是否被按下

Question

在我使用 javascript 提交表单后，我正在尝试检查是否按下了表单类型按钮:

<script>
function DeleteIt(string){
    var pattern = string.indexOf('_');
    var prof_nr = string.substr(pattern+1);
    var delete = confirm("Want to delete it?");

    if( delete == true ){
        document.forms['form'].submit();
    }else{
        alert('Cancel');
    }
}
</script>

<form method="POST" name="form">
<input type="button" name="delete" value="Delete" id="prof_'.$row['code'].'" onclick="DeleteIt(this.id);">
</form>

if(isset($_POST['delete'])){
  echo 'Pressed';
}

但是虽然已经按下了，但并没有遇到这种情况。我不能使用提交类型，因为我已经在表单中有一个用于搜索字段的提交类型。每当我键入内容并按回车键时，它都会触发该功能，这就是我使用按钮的原因。

Answer 1

您在代码中使用了很多语言关键字作为变量名，例如 delete、string。

You can not use reserved words of a programming language as your variable names.

这是工作代码-

<script type="text/javascript">
function DeleteIt(string1){
    var pattern = string1.indexOf('_');
    var prof_nr = string1.substr(pattern+1);
    var delete1 = confirm("Want to delete it?");

    if( delete1 == true ){
        document.forms['form'].submit();
    }else{
        alert('Cancel');
    }
}
</script>

<form method="POST" name="form">
<button name="delete" id="prof_'.$row['code'].'" onclick="DeleteIt(this.id);">delete</button>
</form>

<?php
if(isset($_POST['delete'])){
  echo 'Pressed';
}