C错误: called object is not a function or function pointer

Question

我正在编写一个基于文本的冒险游戏，以提高编码水平，并且我正在用 C 语言编写它，因为这是我在学校使用的语言。我不断收到错误 game.c:28:15: 错误:被调用的对象“room2”不是函数或函数指针。关于如何改进我的代码有什么建议吗？

#include <stdio.h>

int c;
void start(), begin(), room2();

int main(){
   start();
   return 0;
}

void start(){
   printf("Welcome to the Adventure Game! Press s to start\n");
   c = getchar();
   if(c=='s'){begin();}
}

void begin(){
   printf("Text here involving describing a room and directions the player can take, if they press n they will go north\n");
   c = getchar();
   if(c=='n'){room2();}/*This is where I get the error*/
}

void room2(){
   printf("Describes room2 and the player's surroundings, etc\n");
}

Answer 1

尝试将每个函数的定义移动到调用它的行上方，如下所示:

#include <stdio.h>

int c;
void start(), begin(), room2();

void room2(){
   printf("Describes room2 and the player's surroundings, etc\n");
}

void begin(){
   printf("Text here involving describing a room and directions the player can take, if they press n they will go north\n");
   c = getchar();
   if(c=='n'){room2();}/*This is where I get the error*/
}

void start(){
   printf("Welcome to the Adventure Game! Press s to start\n");
   c = getchar();
   if(c=='s'){begin();}
}

int main(){
   start();
   return 0;
}

将c更改为char仍有问题