c - 我想从显示哪个字符出现最频繁或最不频繁的文本文件中读取(键盘或文本文件)？ :)

Question

这是我的代码:

include <stdio.h>

int main()
{
   char str[1000], ch;
   int i, frequency = 0;

   printf("Enter a string: ");
   gets(str);

   printf("Enter a character to find the frequency: ");
   scanf("%c",&ch);

   for(i = 0; str[i] != '\0'; ++i)
   {
       if(ch == str[i])
           ++frequency;
   }

   printf("Frequency of %c = %d", ch, frequency);

   return 0;

我发现我想出的字符代码的频率是相似的。如何实现标准输入或文本文件中出现次数较多/较少的字符？

另外，我应该使用 StreamReader sr = new StreamReader("example.txt") 来读取此代码的普通文本文件吗？

编辑:必须最常使用开关/M，最不经常使用/L。

Answer 1

这是一个好的开始......

include <stdio.h>

int main()
{
   char str[1000], ch,lookup_Chars[256];
   int i, frequency = 0;
   char counter;
   printf("Enter a string: ");
   gets(str);

   printf("Enter a character to find the frequency: ");
   scanf("%c",&ch);

   for(i = 0; str[i] != '\0'; ++i)
   {
       lookup_Chars[str[i]]++;
   }
  for(counter = 0; counter<sizeof(lookup_Chars); counter++)
   {
        printf("Frequency of %c = %d", counter, lookup_Chars[counter]);
   }


   return 0;