c - int 函数返回 ASCII 特殊字符？

Question

我是 C 语言新手，我有一个需要电话号码的程序

getInt 函数如下所示:

int getInt(void) {
    int num;
    char newline = 0;
    do {
        scanf("%d%c", &num, &newline);
        if (newline != '\n') {
            printf("*** Invalid Integer *** <Please enter an integer>: ");
            clearKeyboard();
        }
    } while (newline != '\n');
    return num;
}

定义如下:

void getNumber(struct Number *num) {
    int response;

    printf("Please enter the contact's cell phone number: ");
    *num->cell = getInt();

    printf("Do you want to enter a home phone number? (y or n): ");
    response = yes();

    if (response == 1) {
        printf("Please enter the contact's home phone number: ");
        *num->home = getInt();
    }

    printf("Do you want to enter a business phone number? (y or n): ");
    response = yes();

    if (response == 1) {
        printf("Please enter the contact's business phone number: ");
        *num->business = getInt();
    }
}

主要内容如下:

printf("Numbers: %s|%s|%s\n", contact.number.cell, contact.number.home, contact.number.business);

但由于某种原因，当我输入电话号码时，输出如下: error ascii?

抱歉，我知道图像中的文本，但我无法从调试窗口复制粘贴。

我只是想知道我的代码中可能有什么问题并且它返回 ascii 字母。预先感谢您

Answer 1

好的，在查看@Pablo 评论的类似问题后，它现在可以工作了。他们的答案中有以下代码:

void getNumbers(struct Numbers *numbers) // getNumbers function definition
{
    int result;

    printf("Please enter the contact's cell phone number: ");
    scanf("%s", numbers->cell);
    clear_buffer(stdin);


    if(yes("Do you want to enter a home phone number? (y or n)"))
    {
        printf("Please enter the contact's home phone number: ");
        scanf("%s", numbers->home);
        clear_buffer(stdin);
    }

    if(yes("Do you want to enter a business phone number? (y or n)"))
    {
        printf("Please enter the contact's business phone number: ");
        scanf("%s", numbers->business);
        clear_buffer(stdin);
    }
}

所以我接着复制了同样的想法:

void getNumber(struct Number *num) {
    int response;
    printf("Please enter the contact's cell phone number: ");
    scanf("%10s", num->cell); // I changed this line from:
//  *num->cell = getInt();


    printf("Do you want to enter a home phone number? (y or n): ");
    response = yes();

    if (response == 1) {
        printf("Please enter the contact's home phone number: ");
        scanf("%10s", num->home); // I changed this line from:
//  *num->home = getInt();
    }

    printf("Do you want to enter a business phone number? (y or n): ");
    response = yes();

    if (response == 1) {
        printf("Please enter the contact's business phone number: ");
        scanf("%10s", num->business); // I changed this line from:
//  *num->business = getInt();
    }
}

也许 getInt 函数不适合定义。我不知道如何解释它，但这确实有效。

谢谢大家。