c - Black Jack - 将一张牌添加到手上

Question

我不太确定如何解决。所以我正在编程 blackJack 并且我有我的函数声明(如图所示)，对于我的 add_card_to_hand 函数，我不知道该怎么做。我有 2 个参数，一手牌是我通过引用传递的，因为我要更改其内部值，另一手牌是一张牌；我要添加到手上的牌。那么我该如何将这张卡添加到手上呢？我也不知道类型，我只是输入了 hand_t，它可能是空的。

typedef enum { HEARTS, DIAMONDS, SPADES, CLUBS } suit_t;
typedef enum { ACE = 1, TWO, THREE, FOUR, FIVE, SIX, SEVEN, EIGHT,   NINE, TEN, JACK, QUEEN, KING } value_t;

typedef struct {
    suit_t suit;
    value_t value;
} card_t;

typedef struct {
    card_t* deck;
    int num_decks;
    int nextcard;
} shoe_t;

typedef struct {
    card_t playercards[21];
    int num_cards_in_array;
} hand_t;


hand_t add_card_to_hand(hand_t* hand, card_t card) {



  }

Answer 1

#define MAX_HAND_CARDS 21

typedef struct {
    card_t playercards[MAX_HAND_CARDS];
    int num_cards_in_array;
} hand_t;


int add_card_to_hand(hand_t* hand, const card_t card) {

    if (hand->num_cards_in_array >= MAX_HAND_CARDS) {
        return -1;
    }   

    hand->playercards[hand->num_cards_in_array] = card;
    hand->num_cards_in_array++;

    return 0;
}


int main(int argc, char *argv[]) {

    hand_t *hand = calloc(1, sizeof(hand_t));
    card_t *card = malloc(sizeof(card_t));
    card->suit = HEARTS;
    card->value = ACE;

    if (add_card_to_hand(hand, *card)) {
        printf("failed to add Card\n");
    } else {
        printf("card added\n");
    }
    return 0;
}

不太了解黑 jack ，但这应该有用。