c - SDL2 DestroyRenderer SEGFAULT

Question

我想出了一个我的程序在调用 SDL_DestroyRenderer(SDL_Renderer* renderer); 时抛出 SEGFAULT 的最小示例。

int Setup(t_game* game)
{
    if (SDL_Init(SDL_INIT_VIDEO) != 0)
    {
        fprintf(stderr, "Error Init SDL");
        return 0;
    }

    game->window = SDL_CreateWindow("Client",
                                    SDL_WINDOWPOS_UNDEFINED,
                                    SDL_WINDOWPOS_UNDEFINED,
                                    SCREEN_X,
                                    SCREEN_Y,
                                    SDL_WINDOW_SHOWN);

    game->renderer = SDL_CreateRenderer(game->window, -1, SDL_RENDERER_ACCELERATED);
    SDL_SetRenderDrawColor(game->renderer, 255, 0, 0, 255);

    return 1;
}

void Cleanup(t_game* game)
{  
    SDL_DestroyRenderer(game->renderer);

    SDL_DestroyWindow(game->window);
    SDL_Quit();
}

void Loop(t_game* game)
{
    SDL_Event event;
    int loop = 1;
    while (loop)
    {
        SDL_RenderClear(game->renderer);
        SDL_RenderPresent(game->renderer);
        loop = EventHandler(&event, game);
    }
}

从 main 中调用函数，如下所示:

int main()
{
    t_game game;
    Setup(&game);
    Loop(&game);
    Cleanup(&game);
    return 0;
}

游戏结构声明如下:

typedef struct s_game
{
    SDL_Renderer* renderer;
    SDL_Window* window;
} t_game;

在清理过程中，我收到一个SEGFAULT，表示“无效免费”

Program received signal SIGSEGV, Segmentation fault.
0x00007ffff7ae1f9c in ?? () from /usr/lib/libSDL2-2.0.so.0
(gdb) bt
#0  0x00007ffff7ae1f9c in ?? () from /usr/lib/libSDL2-2.0.so.0
#1  0x00005555555554d0 in Cleanup (game=0x7fffffffdd90)
#2  0x00005555555555e9 in main (argc=1, argv=0x7fffffffdea8)

但是在 gdb 中，在所有 3 个函数中设置断点后，我始终具有相同的渲染器指针。

更新 1:如果我将所有三个函数放在一起，我就不会再出现错误了。更新2:

int EventHandler(SDL_Event* event, t_game* game)
{
    while (SDL_PollEvent(event))
    {
        switch(event->type)
        {
            case SDL_QUIT:
                return 0;
                break;
            case SDL_KEYUP:
                switch (event->key.keysym.sym)
                {
                    case SDLK_ESCAPE:
                        return 0;
                }
        }
    }
    return 1;
}

Answer 1

似乎大页面以某种方式干扰了 SDL2，因为禁用它可以解决无效的空闲错误。