C - 用指针改变字符

Question

我正在尝试制作一款游戏，目前正在制作可重新绑定(bind)的控件。

这些是变量，带有分配的指针

//Controls
char MoveLeft = 'a';
char MoveRight = 'd';
char MoveUp = 'w';
char MoveDown = 's';
char BackButton = 't';
char ConfirmButton = 'y';
char ShowStats = 'u';
char ShowInventory = 'i';
char ShowLegend = 'o';
char ShowControls = 'p';

//Pointers
char *MoveLeftP = &MoveLeft;
char *MoveRightP = &MoveRight;
char *MoveUpP = &MoveUp;
char *MoveDownP = &MoveDown;
char *BackButtonP = &BackButton;
char *ConfirmButtonP = &ConfirmButton;
char *ShowStatsP = &ShowStats;
char *ShowInventoryP = &ShowInventory;
char *ShowLegendP = &ShowLegend;
char *ShowControlsP = &ShowControls;

这是我的控制方法菜单功能

void ControlsMenu(char *MoveLeft, char *MoveRight, char *MoveUp, char *MoveDown, char *BackButton, char *ConfirmButton, char *ShowStats, char *ShowInventory, char *ShowLegend, char *ShowControls) {
//Input
char Input = '0';

//Menu Variables
char ControlNames[] = {MoveLeft,MoveRight,MoveUp,MoveDown,BackButton,ConfirmButton,ShowStats,ShowInventory,ShowLegend,ShowControls};
char *MainMenuNames[] = { "- Move Left", "- Move Right","- Move Up","- Move Down","- Back","- Confirm","- Show Stats","- Show Inventory","- Show Legend"," - Show Controls"};
int MenuChosen = 0;
int *MenuPointer = 0;
MenuPointer = &MenuChosen;
int MinArray = 0;
int MaxArray = 8;
int *ControlPointer = 0;

//Main Loop
do {
    //Loop
    system("cls");
    for (int i = 0; i < 9; i++) {
        printf("%c", ToUpper(ControlNames[i]));
        ShowMenu(MainMenuNames, i, MenuChosen);
    }

    Input = getch();

    ControlMenu(Input, MenuChosen, MenuPointer, MinArray, MaxArray);

    if ((Input == ConfirmButton || Input == ToUpper(ConfirmButton))) {
        system("cls");
        printf("Chaning key binding for %s\n", MainMenuNames[MenuChosen]);
        printf("Old Binding: %c\n", ToUpper(ControlNames[MenuChosen]));
        printf("Press the key you want to bind");
        printf("%d", MenuChosen);
        Input = getch();
        ControlNames[MenuChosen] = Input;
        //Commit Controls

        switch (MenuChosen) {
        case 0: 
            MoveLeft = Input;
            break;
        case 1: 
            MoveRight = Input;
            break;
        case 2: 
            MoveUp = Input;
            break;
        case 3: 
            MoveDown = Input;
            break;
        case 4: 
            BackButton = Input;
            break;
        case 5: 
            ConfirmButton = Input;
            break;
        case 6: 
            ShowStats = Input;
            break;
        case 7: 
            ShowInventory = Input;
            break;
        case 8: 
            ShowLegend = Input;
            break;
        case 9: 
            ShowControls = Input;
            break;
        }


    }
} while (1);
}

这就是它的名字

    ControlsMenu(*MoveLeftP,*MoveRightP,*MoveUpP,*MoveDownP,*BackButtonP,*ConfirmButtonP,*ShowStatsP,*ShowInventoryP,*ShowLegendP,*ShowControlsP);

现在的问题是，由于某些奇怪的原因，字符的文本确实发生了变化，但实际的绑定(bind)保持不变。我可以成功更改的唯一绑定(bind)是ConfirmButton 绑定(bind)，无论我将其更改为什么，它都可以工作，但任何其他内容(例如MoveUp 或MoveDown)都不会更改实际绑定(bind)，而只会更改显示的文本。

Answer 1

不确定 ConfirmButton 发生了什么，但我发现 switch 语句中的内容存在问题。以 MoveLeft = Input; 为例。MoveLeft 是函数中的 char* (即内存地址)，但 Input 是一个 char (即ASCII 值)。要将Input分配给MoveLeft指向的内存，您需要执行*MoveLeft = Input。您的编译器应该向您发出有关不兼容赋值的警告。其余的也类似。

顺便说一句，C 变量名称的约定是使用小写字母并加下划线，或者有些人使用驼峰式命名，首字母小写。而且给所有函数参数赋予与某些全局变量相同的名称会令人困惑。