c - 将用户输入获取到动态数组 C 时出现问题

Question

我似乎无法将用户输入放入 C 中的动态数组中。

#include "stdio.h"

int main(void){
    int counter = 0;
    int x = 1;
    int i;
    printf("Enter the number of teams playing in the league: \n");
    scanf("%d", &i);
    char teams[i];
    for (counter = 0; counter < i; counter++){
        char teams[counter];
        printf("Enter team names: \n");
        scanf("%s", teams);
    }
    for (counter = 0; counter < i; counter++){
        char teams[counter][10];
        printf(" Team %d is %s \n", x, *teams);
        x++;
    }
}

当我运行此代码时，我得到以下输出，

Enter the number of teams playing in the league: 2

Enter team names: Team1

Enter team names: Team2

 Team 1 is Team1 

 Team 2 is \320\365\277\357\376 

Program ended with exit code: 0

无法找出我的错误。希望得到任何和所有的帮助。

谢谢!

Answer 1

存在一些基本错误，尤其是您对指针和 C 语言概念的理解。 “team”是一个 char 指针数组，而 char groups[i] 不太正确；一种正确的方法是为团队名称的集合动态分配内存。通过将下面的代码与您的代码进行比较，我相信您可以发现出错的地方。 PS:我在scanf中使用格式字符“m”为团队名称动态分配内存。

int main(int argc, char **argv){
    int counter = 0;
    int i, ret;
    char **teams;
    printf("Enter the number of teams playing in the league: \n");
    scanf("%d", &i); // check return value yourself
    teams=(char **)malloc(sizeof(char *)*i);
    if(NULL==teams) perror("not enough memory"), exit(1);
    for (counter = 0; counter < i; counter++){
        printf("Enter team names: \n");
        ret=scanf("%ms", &teams[counter]);
        if(ret<1)//hanndle error. i'll just quit.
            exit(-1);
    }
    for (counter = 0; counter < i; counter++){
        printf(" Team %d is %s \n", counter+1, teams[counter]);
        free(teams[counter]);
    }
    free(teams);    
}