c# - FormClosing 后计时器滴答？

Question

在 myForm_FormClosing 之后是否有任何机会调用 timer_Tick在下面的代码中。

如果有机会:在 myForm_FormClosing 中调用 timer.Stop() 是否足以避免在 myForm_FormClosing 之后调用 timer_Tick？

using System;
using System.Windows.Forms;
using System.ComponentModel;

namespace Test
{
    static class Program
    {
        [STAThread]
        static void Main()
        {
            Application.EnableVisualStyles();
            Application.SetCompatibleTextRenderingDefault(false);
            Application.Run(new MyForm());
        }
    }

    class MyForm : Form
    {
        private IContainer components;
        private Timer timer;

        protected override void Dispose(bool disposing)
        {
            if (disposing && (components != null))
            {
                components.Dispose();
            }
            base.Dispose(disposing);
        }

        public MyForm()
        {
            components = new Container();
            timer = new Timer(components);

            timer.Interval = 50;
            timer.Tick += timer_Tick;
            timer.Enabled = true;

            FormClosing += myForm_FormClosing;
        }

        private void timer_Tick(object sender, EventArgs e)
        {
        }

        private void myForm_FormClosing(object sender, FormClosingEventArgs e)
        {
        }
    }
}

更新:在收到一些提示(感谢帮助)后，我基本上选择了以下代码来实现我想要的。请注意，调用 myForm_FormClosing 后仍然可以调用 timer1_Tick!这个解决方案只是引入了一个标志(我称之为 doWork)，它在调用 myForm_FormClosing 之后停止执行 timer1_Tick 中的代码。

using System;
using System.Windows.Forms;
using System.ComponentModel;

namespace Test
{
    static class Program
    {
        [STAThread]
        static void Main()
        {
            Application.EnableVisualStyles();
            Application.SetCompatibleTextRenderingDefault(false);
            Application.Run(new MyForm());
        }
    }

    class MyForm : Form
    {
        private IContainer components;
        private Timer timer;
        private bool  doWork = true;

        protected override void Dispose(bool disposing)
        {
            if (disposing && (components != null))
            {
                components.Dispose();
            }
            base.Dispose(disposing);
        }

        public MyForm()
        {
            components = new Container();
            timer = new Timer(components);

            timer.Interval = 50;
            timer.Tick += timer_Tick;
            timer.Enabled = true;

            FormClosing += myForm_FormClosing;
        }

        private void timer_Tick(object sender, EventArgs e)
        {
            if (doWork)
            {
                //do the work
            }
        }

        private void myForm_FormClosing(object sender, FormClosingEventArgs e)
        {
            doWork = false;
        }
    }
}

Answer 1

是的，这是可能的。根据the docs ...

Occurs before the form is closed.

When a form is closed, it is disposed, releasing all resources associated with the form.

直到 FormClosing 事件之后，计时器才会被释放。这是一个非常人为的例子来说明它是如何发生的。在调用 FormClosing 之后，您将看到您在 Timer tick 上命中了调试器断点。

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;
using System.Diagnostics;
using System.Threading.Tasks;
using System.Threading;

namespace WindowsFormsApplication1
{
    public partial class Form1 : Form
    {
        private System.Windows.Forms.Timer _time = new System.Windows.Forms.Timer();
        private Task _t1 = null;
        private Task _t2 = null;
        private bool _closingFlag = false;
        public Form1()
        {
            InitializeComponent();

            _time.Interval = 50;
            _time.Tick += (s, e) => { 
                textBox1.Text = DateTime.Now.ToString();
                if (_closingFlag) Debugger.Break();
            };

            _time.Start();
        }

        private void Form1_FormClosing(object sender, FormClosingEventArgs e)
        {
            _closingFlag = true;

            _t1 = Task.Factory.StartNew(() => { Thread.Sleep(1000); });
            _t2 = Task.Factory.StartNew(() => { Thread.Sleep(1000); });

            Task.WaitAll(_t1, _t2);
        }
    }
}