c - 如何在函数内调用带有参数的函数？

Question

尝试在“PayInput”中调用函数“TaxInput”，以便我的税款和净工资可以与每个员工的个人资料一起打印。相反，它会在最后一名员工输出后打印所有“税”和“净工资”。我尝试在“PayInput”中使用参数调用它，但它无法编译。如果我取出参数，那么它会完全跳过该函数，并且根本不打印税费或 netPay。请参见下文:

Pay to: Employee1
Hours worked: 45.00
Hourly rate: $1.00
Gross pay: $52.50
Base pay: $45.00
Overtime pay: $7.50

Pay to: Employee2
Hours worked: 45.00
Hourly rate: $1.00
Gross pay: $52.50
Base pay: $45.00
Overtime pay: $7.50
Taxes paid: $10.50
Taxes paid: $10.50

我的代码:

#include <stdio.h>

void PayInput(char empNames[5][32], float empHours[], float empRates[], 
             float overtime[], float overtime_pay[], float gross[],
             float basepay[], float netPay[], float tax[])
{
    for (int i = 0; i < Times; i++) 
    {
        printf("\n\nPay to: %s \n", empNames[i]);
        printf("Hours worked: %.2f \n", empHours[i]);
        printf("Hourly rate: $%.2f \n", empRates[i]);

        if (empHours[i] > 40) 
        {
            overtime[i] = empHours[i] - 40;
            overtime_pay[i] = overtime[i] * (empRates[i] * 1.5);
            printf("Gross pay: $%.2f \n", gross[i] = empHours[i] * 
      empRates[i] + overtime_pay[i]);
            printf("Base pay: $%.2f \n", basepay[i] = empHours[i] 
    * empRates[i]);
            printf("Overtime pay: $%.2f \n", overtime_pay[i]);
        }
        else 
        {
            printf("Gross income: $%.2f \n", gross[i] = 
    empHours[i] * empRates[i]);
            printf("Base pay: $%.2f \n", basepay[i] = empHours[i] 
    * empRates[i]);
        }
    }
}

void TaxInput(float gross[], float tax[], float netPay[])
{
    for (int i = 0; i < Times; i++)
    {
        tax[i] = gross[i] * 20 / 100;
        printf("Taxes paid: $%.2f \n", tax[i]);

        netPay[i] = gross[i] - tax[i];
        printf("Net Pay: $%.2f \n", netPay[i]);
    }
}

float TotalGross=0;

void allGross(float gross[])
{
    for (int i = 0; i < Times; i++)
    {
        TotalGross += gross[i];
    }
    printf("Total paid to employees: $%.2f", TotalGross);
}   

int main()
{
    char empNames[5][32];
    float empRates[5], empHours[5], overtime[5], overtime_pay[5], 
        gross[5], basepay[5], tax[5], netPay[5];

    NameInput(empNames, empHours, empRates);

    printf("\n\n-------------------------------------------\n");
    printf("-------------------------------------------\n");

    PayInput(empNames, empHours, empRates, overtime, overtime_pay, gross, 
        basepay, tax);

    TaxInput(gross, tax, netPay);

    printf("\n\n");

    allGross(gross);

    printf("\n\n");
}

Answer 1

it is printing all "tax" … after the last employee's output.

当然是这样，因为您现在有一个函数 PayInput()，它可以循环打印所有 Times 支付数据，然后是函数 TaxInput() 循环打印所有Times 税务数据。鉴于这种不切实际的程序结构，最简单的解决方法是通过删除行来合并两个函数

    }
}

void TaxInput(float gross[], float tax[], float netPay[])
{
    for (int i = 0; i < Times; i++)
    {

并且仅调用

    PayInput(empNames, empHours, empRates, overtime, overtime_pay, gross, 
        basepay, netPay, tax);

在main()中。

除此之外，评论者关于使用结构的建议非常值得考虑。