c - 为什么这个键盘输入不作为 C 中的 Char

Question

这个问题已经有答案了:

scanf() leaves the newline character in the buffer (7 个回答)

已关闭 3 年前。

我真的很困惑，为什么当我为该代码的 char 值分配付款选项时，它不作为 char 输入。我尝试将我的代码更改为几种方法，但这些方法都没有解决我的问题。

#include<stdio.h>
int main(){

char Ptype;
char Rtype;
int noRoom;
int noNight;
int noRooms;

float total;
char ch;

printf("Please enter the room type\n");
scanf("%c",&Rtype);

if(Rtype =='D' || Rtype == 'd'){

    printf("Please Enter the no of night ");
    scanf("%d",&noNight);

    printf("Please Enter the no of room ");
    scanf("%d",&noRooms);

    printf("Please enter the paying method");
    scanf("%c",&Ptype); // input is not taking as char 

if(Ptype=='M' || Ptype == 'N'){

    total=noNight*5000;
    printf("%fTotal amount is", total );

    }

    else if (Rtype=='c' || Rtype == 'C'){

    total=noNight*5000*0.10;
    printf("%fTotal amount is", total);

   }}

   return 0;
   }

Answer 1

scanf 中 %c 说明符之前的空格指示它跳过任意数量的空格。换句话说，从标准输入读取，直到找到非空白字符或键盘中断

 scanf(" %c",&Ptype);

What does space in scanf mean?