c - 将 getchar() 的结果分配给结构成员指针

Question

我一直在尝试创建一个函数，将 getchar() 分配给指向结构成员 (last_name) 的指针 (p_customers) )，但我不断收到编译器错误或段错误。这是我到目前为止所拥有的:

/* A customer account receivable record                               */
struct customer
{
   char  last_name[MAX_NAME_LENGTH+1]; /* Customer last name          */
   float amount;                       /* Amount the customer owes    */
   int   priority;                     /* Customer priority           */
};

void get_customers(struct customer *p_customers_start, 
                               int number_customers)
{
   struct customer *p_customers; /* Points to the account receivable  */
                                 /* customer                          */
   char            *p_last_name; /* Points to the last name character */

   /* Loop processing account receivable customer data                */
   for (p_customers=p_customers_start;
       (p_customers-p_customers_start) < number_customers;
        p_customers++)
   {
      /* Print out account receivable customer                        */
      printf(   "\nCustomer #%d:", 
               *p_customers - *p_customers_start + 1);

      /* Obtain last name of customer                                 */
      printf("   \nEnter the customer's last name: ");
      getchar();
      do
      {
          p_customers->last_name++ = getchar();
      }
      while(*p_last_name != NEW_LINE);
      p_last_name = END_OF_STRING;
   }
}

我不知道问题是什么，但有人可以告诉我如何解决它吗？

Answer 1

能贴出完整的代码吗？上面的代码太晦涩，无法给出任何正确分析的提示。但是，我可以根据假设做出以下评论: p_customers->last_name 和 p_last_name 可能不是指同一位置。结果，“last_name++ = getchar()”继续读取字符并尝试输入超出其限制的地址。这会导致段错误。