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c - 与 c 中的大小相比,为什么 float 的输出包含更多零

转载 作者:行者123 更新时间:2023-11-30 16:06:07 26 4
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#include<stdio.h>
int main()
{
float a = 1.5;
printf("%f", a);
return 0;
}

显示的输出为1.500000。为什么它包含 5 个零?

最佳答案

默认情况下打印时, double (和 float )具有六位精度(小数点后)。

来自 printf(3) 手册页:

The double argument is rounded and converted to decimal notation in the style [-]ddd.ddd, where the number of digits after the decimal-point character is equal to the precision specification. If the precision is missing, it is taken as 6; if the precision is explicitly zero, no decimal-point character appears. If a decimal point appears, at least one digit appears before it.

关于c - 与 c 中的大小相比,为什么 float 的输出包含更多零,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/60047650/

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