c# - 序列化并忽略抛出异常的属性

Question

假设我有一个类:

public class Cat
{
    public int Hunger {get; set;}
    public int Sleepiness {get; set;}
    public int Usefullness {
      get { throw new DivideByZeroException(); }
    }
}

是否可以序列化如下:

public ActionResult GetMyCat()
{
     Cat c = new Cat()
    {
        Hunger = 10,
        Sleepiness = 10
    };

    return Json(c);
}

我无法修改“Cat”类。我能否让 MVC JSON Serializer 忽略一个属性抛出的错误(如果它抛出错误)并只给我该属性的空值/默认值？

Answer 1

创建将返回正确对象的类扩展

public static class CatExtensions
 {
        public static object GetObject(this Cat value)
        {
            return new
            {
                Hunger = value.Hunger,
                Sleepiness = value.Sleepiness
            }
        }
    }