C# - 映射器和配置文件

Question

我有两个类(class):

public class Customer
{
    public string FirstName { get; set; }

    public string LastName { get; set; }

    public Product Product { get; set; }
}

public class Product
{
    public int ProductNumber { get; set; }

    public string ProductColor { get; set; }
}


public class Customer_
{
    public string FirstName { get; set; }

    public string LastName { get; set; }

    public Article Article { get; set; }
}

public class Article
{
    public int ArticleNumber { get; set; }

    public string ArticleColor { get; set; }
}

还有一个实例:

Customer Cus = new Customer()
{
    FirstName = "FirstName1",
    LastName = "LastName1",
    Product = new Product()
    {
        ProductColor = "ProductColor1",
        ProductNumber = 11
    }
};

我想从我的实例 Cus 创建一个类 Customer_ 的实例

我使用自动映射器:

MapperConfiguration Config = new MapperConfiguration(cfg =>
{
    cfg.CreateMap<Customer, Customer_>()
    .ForMember(a => a.Article, b => b.MapFrom(c => c.Product));

    cfg.CreateMap<Product, Article>()
    .ForMember(a => a.ArticleColor, b => b.MapFrom(c => c.ProductColor))
    .ForMember(a => a.ArticleNumber, b => b.MapFrom(c => c.ProductNumber));                
});

IMapper Mapper = Config.CreateMapper();
var cus_ = Mapper.Map<Customer, Customer_>(Cus);

它可以工作，但我想从配置文件创建 MapperConfiguration。像这样:

<?xml version="1.0" encoding="utf-8" ?>
<configuration>
  <Automapper>
    <Column source="Product" destination="Article"/>
    <Column source="Product.ProductColor" destination="Article.ArticleColor"/>
    ...
    ...
    ...
  </Automapper>
</configuration>

这可能吗？

Answer 1

无法使用 AutoMapper 开箱即用地执行此操作，但使用基于类型的 AutoMapper 版本，您当然可以这样做:

cfg.CreateMap(typeof(Customer), typeof(Customer_))
    .ForMember("Product").MapFrom("Article");

因此，您只需要遍历 XML，加载类型，并针对每个子节点，为您拥有的两个字符串调用 MapFrom。

您的 XML 看起来不够完整，无法执行此操作，您需要类似以下内容:

<TypeMap SourceType="Customer" DestinationType="Customer_">
    <PropertyMap Member="Product" MapFrom="Article">
</TypeMap>

等等